我在操作栏中有一个带有搜索按钮的Activity(MainActivity)。它通过一些输入字符串进行搜索,并在另一个Activity(SearchResultsActivity)的ListView中显示结果。用户可以单击任何结果来选择它。
我想将用户选择的值返回到主活动,但它不起作用。我查看了documentation,但我没有发现任何相关内容。 我尝试在结果活动中使用setResult(Intent),但主活动中的onActivityResult()永远不会被调用。
我做错了什么?我该怎么办?
的AndroidManifest.xml:
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="foo.bar" >
<!-- ... -->
<uses-sdk android:minSdkVersion="11" />
<application
android:allowBackup="true"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name">
<!-- Main Activity -->
<activity
android:name=".MainActivity"
android:label="@string/title_activity_main">
<meta-data
android:name="android.app.default_searchable"
android:value=".SearchResultsActivity" />
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<!-- Search results activity -->
<activity android:name=".SearchResultsActivity"
android:parentActivityName=".MainActivity" >
<intent-filter>
<action android:name="android.intent.action.SEARCH" />
</intent-filter>
<meta-data
android:name="android.app.searchable"
android:resource="@xml/searchable" />
</activity>
</application>
</manifest>
menu.xml文件:
<menu xmlns:tools="http://schemas.android.com/tools"
xmlns:android="http://schemas.android.com/apk/res/android"
tools:context=".MainActivity">
<!-- Search -->
<item android:id="@+id/action_search"
android:icon="@drawable/ic_action_search"
android:title="@string/action_search"
android:showAsAction="always"
android:actionViewClass="android.widget.SearchView" />
<!-- ... -->
</menu>
MainActivity:
public class MainActivity extends FragmentActivity {
// ...
@Override
public boolean onCreateOptionsMenu(Menu menu) {
final MenuInflater menuInflater = getMenuInflater();
menuInflater.inflate(R.menu.activity_main_menu, menu);
// Associate searchable configuration with the SearchView
SearchManager searchManager = (SearchManager) getSystemService(Context.SEARCH_SERVICE);
SearchView searchView = (SearchView) menu.findItem(R.id.action_search).getActionView();
searchView.setSearchableInfo(searchManager.getSearchableInfo(getComponentName()));
return true;
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
// never gets called!
super.onActivityResult(requestCode, resultCode, data);
}
// ...
}
SearchResultsActivity:
public class SearchResultsActivity extends Activity {
private ListView listResults;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.search_results);
// get the action bar
ActionBar actionBar = getActionBar();
// Enabling Back navigation on Action Bar icon
actionBar.setDisplayHomeAsUpEnabled(true);
listResults = (ListView) findViewById(R.id.listResults);
handleIntent(getIntent());
}
@Override
protected void onNewIntent(Intent intent) {
setIntent(intent);
handleIntent(intent);
}
/**
* Handling intent data
*/
private void handleIntent(Intent intent) {
if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
String query = intent.getStringExtra(SearchManager.QUERY);
final Serializable[] results = find(query);
listResults.setAdapter(new ArrayAdapter<BusLine>(this, R.layout.list_view, busLines));
listResults.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
Serializable selectedResult = (Serializable) parent.getItemAtPosition(position);
setResult(RESULT_OK, new Intent().putExtra("result", selectedResult));
finish();
}
});
}
}
}
答案 0 :(得分:0)
我可以理解为什么你会认为你会使用setResult和onActivityResult来处理搜索结果活动中的点击,但这不是它的工作原理。仅当您使用startActivityForResult启动活动时才会应用这些功能 - 而不是在显示搜索结果时。
解决方案是以正常方式调用MainActivity上的startActivity,即不使用活动结果。像这样:
listResults.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
Serializable selectedResult = (Serializable) parent.getItemAtPosition(position);
Intent intent = new Intent();
intent.putExtra("result", selectedResult);
intent.setClass(SearchResultsActivity.this, MainActivity.class);
startActivity(intent);
finish();
}
});
现在您还需要在MainActivity中捕获此搜索结果,但您需要确保处理正常情况以及搜索结果案例:
@Override
protected void onCreate(Bundle savedInstanceState) {
Intent intent = getIntent();
if (intent.hasExtra("result")) {
// Launched from search results
Serializable selectedResult = (Serializable) intent.getSerializableExtra("result");
...
}
...
}