如何将字符串切成对

Question

对于我正在进行的项目，我需要在输入中进行配对，但我无法弄清楚如何，我可以使用一些帮助。
它是怎么回事：

2209222717080109

我希望它成为：

["22","09","22","27","17","08","01","09"]

Answer 1

"2209222717080109".scan /../
  #=> ["22", "09", "22", "27", "17", "08", "01", "09"] 

Answer 2

input = "2209222717080109"
input.chars.each_slice(2).map(&:join)
["22", "09", "22", "27", "17", "08", "01", "09"]

Answer 3

Convert it to a string，convert that into an array of characters，然后获取两个字符each consecutive slice，join each of those slices一起：

2209222717080109.to_s.chars.each_slice(2).map(&:join)
#=> ["22", "09", "22", "27", "17", "08", "01", "09"]