SyntaxError:语法无效

时间:2015-01-19 05:46:58

标签: python session request screen-scraping

我的代码中有语法错误,我不明白 我需要帮助,我没有看到我的错误

      headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/39.0.2171.95 Safari/537)'}
      session = requests.Session()
      response = session.get(olinks, headers=headers)
      soup = BeautifulSoup(response.content)
      oname = soup.find("title")
      if oname.text.find('Saison') >= 0:
          regexp = r'(.*?\s+-\s+S)aison\s+(\d+)\s+\xc9.*?(\d+)(.*)'
          subst = "{title} {season:02d} Ep {episode}"
      else:
          regexp = r'(.*?\s+-)(\s+)\xc9.*?(\d+)(.*)'
          subst = "{title} Ep {episode}"
      oname_cleanedup = re.sub(regexp, 
                         lambda m: subst.format(title=m.group(1), season=int(m.group(2)) if m.group(2).find(" ")==-1 else "", episode=m.group(3))
             oname.text)
抱歉

File "start.py", line 41
    oname.text)
        ^
SyntaxError: invalid syntax

1 个答案:

答案 0 :(得分:0)

您在,开头的行末尾缺少逗号lambda。如果您要查看语法错误的全文,它会告诉您确切的位置,因此请在它之前查看错误或遗漏的内容。