“溢出”菜单中的“自定义菜单”项

Question

我应该如何制作自定义MenuItem，与所附图片菜单中的第一行完全相同（Google Chrome应用的截图）

我在onCreateOptionsMenu中尝试了以下代码，其中R.layout.menu_top_row是第一行的布局。但在我的情况下只出现一个空行？我可以显示其余选项，但无法显示第一行。

View child = getLayoutInflater().inflate(R.layout.menu_top_row, null);
    MenuItem menuItem=menu.add("");
    menuItem.setActionView(child);

Answer 1

Taken from this stack overflow answer：

PopupMenu用于显示Menus，并且确实没有一种自定义菜单项外观的好方法。如果您想要更灵活的内容，您的答案是ListPopupWindow。

private static final String TITLE = "title";
private static final String ICON = "icon";

private List<HashMap<String, Object>> data = new ArrayList<HashMap<String, Object>>();

// Use this to add items to the list that the ListPopupWindow will use
private void addItem(String title, int iconResourceId) {
    HashMap<String, Object> map = new HashMap<String, Object>();
    map.put(TITLE, title);
    map.put(ICON, iconResourceId);
    data.add(map);
}

// Call this when you want to show the ListPopupWindow
private void showListMenu(View anchor) {
    ListPopupWindow popupWindow = new ListPopupWindow(this);

    ListAdapter adapter = new SimpleAdapter(
            this,
            data,
            android.R.layout.activity_list_item, // You may want to use your own cool layout
            new String[] {TITLE, ICON}, // These are just the keys that the data uses
            new int[] {android.R.id.text1, android.R.id.icon}); // The view ids to map the data to


    popupWindow.setAnchorView(anchor);
    popupWindow.setAdapter(adapter);
    popupWindow.setWidth(400); // note: don't use pixels, use a dimen resource
    popupWindow.setOnItemClickListener(myListener); // the callback for when a list item is selected
    popupWindow.show();
}