Question

我遇到了为我的Web应用程序设置处理程序的问题，我想要的是：使用doGet和doPost方法处理由HTTPServlet处理的一些请求（如何从这些方法中加载JSP页面？）以及能够加载静态内容（html，JS，CSS）

我现在正在设置它的方式，我只能有一个或另一个，我不能同时工作。

我会解释：

Server server = new Server(5000);

   // This is the resource handler for JS & CSS

    ResourceHandler resourceHandler = new ResourceHandler();

    resourceHandler.setResourceBase(".");

    resourceHandler.setDirectoriesListed(false);

   // This is the context handler for the HTTPServlet

    ServletContextHandler context = new ServletContextHandler(ServletContextHandler.SESSIONS);

    context.setContextPath("/");

    context.addServlet(new ServletHolder(new Main()),"/*");

   // this is the Handler list for both handlers

    HandlerList handlerList = new HandlerList();

    handlerList.setHandlers(new Handler[] { context ,resourceHandler});

/*

     If I add them in this order, all requests will be handled by the "context" and no static resource is loaded

     If I invert the order, the index page page is loaded by the resource handler, which means, If I activate directory listings, it gives me a list of all directories, otherwise it's just a blank page

     I tried working with a WebAppContext to load JSP pages but I still had some problems with which handler should handle which requests

*/

    server.setHandler(handlerList);

    server.start();

    server.join();

谢谢

**编辑：**

我遇到的问题是我的HTTP servlet的行为方式如下：处理所有请求，不为资源处理程序留下任何内容，因此当脚本请求.js脚本时，它会返回一个空的html页面。这是一个例子：

    WebAppContext root = new WebAppContext();

    root.setParentLoaderPriority(true);
    root.setContextPath("/");
    root.setResourceBase(".");
    root.setWelcomeFiles(new String[] {"test.jsp"});
    root.addServlet(new ServletHolder(new Main()),"/*");

    HandlerList handlerList = new HandlerList();
    handlerList.setHandlers(new Handler[] { root });

在这个例子中，当使用没有Main servlet的根处理程序时，它会加载所有静态内容和jsp页面，但是在添加主servlet时，它不再加载任何静态内容，并响应所有静态内容请求。一个空的html页面。

Answer 1

使用servlet时，servlet链的末尾总会有一个终止。

它可能是：

DefaultServlet（使用完整WebAppContext时）
Default404Servlet（使用ServletContextHandler等简单设置时）

如果你想让ResourceHandler for提供静态内容，请使用DefaultServlet用于您自己的目的（它是一个更好的选择并支持更多功能。例如范围请求，缓存，自动-gzip，内存映射文件服务等）

示例：

package jetty;

import org.eclipse.jetty.server.Server;
import org.eclipse.jetty.server.ServerConnector;
import org.eclipse.jetty.servlet.DefaultServlet;
import org.eclipse.jetty.servlet.ServletContextHandler;
import org.eclipse.jetty.servlet.ServletHolder;

public class ManyDefaultServlet
{
    public static void main(String[] args)
    {
        System.setProperty("org.eclipse.jetty.servlet.LEVEL","DEBUG");

        Server server = new Server();
        ServerConnector connector = new ServerConnector(server);
        connector.setPort(8080);
        server.addConnector(connector);

        // Setup the basic application "context" for this application at "/"
        // This is also known as the handler tree (in jetty speak)
        ServletContextHandler context = new ServletContextHandler(ServletContextHandler.SESSIONS);
        context.setContextPath("/");
        server.setHandler(context);

        // The filesystem paths we will map
        String homePath = System.getProperty("user.home");
        String pwdPath = System.getProperty("user.dir");

        // Fist, add special pathspec of "/home/" content mapped to the homePath
        ServletHolder holderHome = new ServletHolder("static-home", DefaultServlet.class);
        holderHome.setInitParameter("resourceBase",homePath);
        holderHome.setInitParameter("dirAllowed","true");
        holderHome.setInitParameter("pathInfoOnly","true");
        context.addServlet(holderHome,"/home/*");

        // Lastly, the default servlet for root content
        // It is important that this is last.
        ServletHolder holderPwd = new ServletHolder("default", DefaultServlet.class);
        holderPwd.setInitParameter("resourceBase",pwdPath);
        holderPwd.setInitParameter("dirAllowed","true");
        context.addServlet(holderPwd,"/");

        try
        {
            server.start();
            server.dump(System.err);
            server.join();
        }
        catch (Throwable t)
        {
            t.printStackTrace(System.err);
        }
    }
}

如何配置Jetty处理程序？

1 个答案: