Question

我正在使用OpenAL-Soft进行项目，现在我正在尝试决定是否需要实施OpenAL源池。

源池有点麻烦（我需要编写代码到＆＃34;分配＆＃34;来源，以及以某种方式决定何时可以＆＃34;释放＆＃34;），但如果数量为可以由OpenAL生成的来源是有限的。

由于OpenAL-Soft是OpenAL API的软件实现，我想知道它可以生成的源数量是否实际上受底层硬件的限制。从理论上讲，由于所有混合都是在软件中完成的，因此可能不需要每个源实际使用一个硬件通道。

但是，我不确定。我该怎么办？

Answer 1

看来OpenAL-Soft确实对源数有一个上限，可以在配置文件中定义。默认值似乎是256.由于相关的CPU和内存成本，限制源的数量是有意义的。看起来我终究会最终实现一个源池。

Answer 2

我只是偷看了它的标题......没有看到任何弹出的东西。这是工作代码，它合成然后呈现音频缓冲数据...你可以看看它是否适应你所需数量的来源

// gcc -o openal_play_wed   openal_play_wed.c  -lopenal -lm

#include <stdio.h>
#include <stdlib.h>    // gives malloc
#include <math.h>


#ifdef __APPLE__
#include <OpenAL/al.h>
#include <OpenAL/alc.h>
#elif __linux
#include <AL/al.h>
#include <AL/alc.h>
#endif

ALCdevice  * openal_output_device;
ALCcontext * openal_output_context;

ALuint internal_buffer;
ALuint streaming_source[1];

int al_check_error(const char * given_label) {

    ALenum al_error;
    al_error = alGetError();

    if(AL_NO_ERROR != al_error) {

        printf("ERROR - %s  (%s)\n", alGetString(al_error), given_label);
        return al_error;
    }
    return 0;
}

void MM_init_al() {

    const char * defname = alcGetString(NULL, ALC_DEFAULT_DEVICE_SPECIFIER);

    openal_output_device  = alcOpenDevice(defname);
    openal_output_context = alcCreateContext(openal_output_device, NULL);
    alcMakeContextCurrent(openal_output_context);

    // setup buffer and source

    alGenBuffers(1, & internal_buffer);
    al_check_error("failed call to alGenBuffers");
}

void MM_exit_al() {

    ALenum errorCode = 0;

    // Stop the sources
    alSourceStopv(1, & streaming_source[0]);        //      streaming_source
    int ii;
    for (ii = 0; ii < 1; ++ii) {
        alSourcei(streaming_source[ii], AL_BUFFER, 0);
    }
    // Clean-up
    alDeleteSources(1, &streaming_source[0]);
    alDeleteBuffers(16, &streaming_source[0]);
    errorCode = alGetError();
    alcMakeContextCurrent(NULL);
    errorCode = alGetError();
    alcDestroyContext(openal_output_context);
    alcCloseDevice(openal_output_device);
}

void MM_render_one_buffer() {

    /* Fill buffer with Sine-Wave */
    // float freq = 440.f;
    float freq = 100.f;
    float incr_freq = 0.1f;

    int seconds = 4;
    // unsigned sample_rate = 22050;
    unsigned sample_rate = 44100;
    double my_pi = 3.14159;
    size_t buf_size = seconds * sample_rate;

    short * samples = malloc(sizeof(short) * buf_size);

   printf("\nhere is freq %f\n", freq);
    int i=0;
    for(; i<buf_size; ++i) {
        samples[i] = 32760 * sin( (2.f * my_pi * freq)/sample_rate * i );

        freq += incr_freq;
        // incr_freq += incr_freq;
        // freq *= factor_freq;

        if (100.0 > freq || freq > 5000.0) {

            incr_freq *= -1.0f;
        }
    }

    /* upload buffer to OpenAL */
    alBufferData( internal_buffer, AL_FORMAT_MONO16, samples, buf_size, sample_rate);
    al_check_error("populating alBufferData");

    free(samples);

    /* Set-up sound source and play buffer */
    // ALuint src = 0;
    // alGenSources(1, &src);
    // alSourcei(src, AL_BUFFER, internal_buffer);
    alGenSources(1, & streaming_source[0]);
    alSourcei(streaming_source[0], AL_BUFFER, internal_buffer);
    // alSourcePlay(src);
    alSourcePlay(streaming_source[0]);

    // ---------------------

    ALenum current_playing_state;
    alGetSourcei(streaming_source[0], AL_SOURCE_STATE, & current_playing_state);
    al_check_error("alGetSourcei AL_SOURCE_STATE");

    while (AL_PLAYING == current_playing_state) {

        printf("still playing ... so sleep\n");

        sleep(1);   // should use a thread sleep NOT sleep() for a more responsive finish

        alGetSourcei(streaming_source[0], AL_SOURCE_STATE, & current_playing_state);
        al_check_error("alGetSourcei AL_SOURCE_STATE");
    }

    printf("end of playing\n");

    /* Dealloc OpenAL */
    MM_exit_al();

}   //  MM_render_one_buffer

int main() {

    MM_init_al();

    MM_render_one_buffer();
}

OpenAL-Soft的来源数量有上限吗？

2 个答案: