用RestSharp返回一个简单的Guid

时间:2015-01-28 11:26:38

标签: c# restsharp

RestSharp无法反序列化普通Guid的响应。

[Route("User/BeginSession")]
[HttpGet]
public Guid BeginSession()
{
    return Guid.NewGuid();
}

此测试失败:

[Fact]
public void BeginSession_MadeAsARestRequest_Succeeds()
{
    var client = new RestClient("http://localhost/xyz");
    var request = new RestRequest("User/BeginSession");

    var a = client.Execute(request);

    var result = client.Execute<Guid>(request).Data;

    Assert.NotEqual(
        Guid.Parse("{00000000-0000-0000-0000-000000000000}"),
        result);
}

我必须用一个类包装Guid才能让它工作:

public class GuidResponse
{
    public Guid Guid { get; set; }
}

[Route("User/BeginSession2")]
[HttpGet]
public GuidResponse BeginSession2()
{
    return new GuidResponse
    {
        Guid = Guid.NewGuid()
    };
}

此测试通过:

[Fact]
public void BeginSession2_MadeAsARestRequest_Succeeds()
{
    var client = new RestClient("http://localhost/xyz");
    var request = new RestRequest("User/BeginSession2");

    var result = client.Execute<GuidResponse>(request).Data;

    Assert.NotEqual(
        Guid.Parse("{00000000-0000-0000-0000-000000000000}"),
        result.Guid);
}

这是预期的行为吗?

1 个答案:

答案 0 :(得分:2)

我想这是因为只返回一个GUID并不是有效的JSON。它将作为字符串返回,而不是作为JavaScript对象返回,例如{ "id": "4bae9421-4fe0-4294-a659-9bc37388344b" }