Question

我在python中使用any（）

from inActivePhrase import phrase

detailslist=[]

for detail in detailslist:
    inactive = any(term in detail for term in phrase)

短语将包含下面的字符串列表

phrase = ["not active","Closed",etc..]

功能正常。但我想得到细节中存在的短语。

示例：

  detail = "this is not active"
  inactive = any(term in detail for term in phrase)
   if inactive:
        print('matched phrase' + term) //how can i do this

其中＆＃34;不活跃＆＃34;是匹配的短语。所以我想打印它。

我该怎么做？谁能帮我？

谢谢，

Answer 1

你可以有几个术语匹配的细节

detail = "this is not active"
inactive = [term for term in phrase if term in detail]
if inactive:
    print('matched phrases' + inactive)

Answer 2

使用next，它会在找到第一个匹配项后立即迭代并停止。如果没有找到任何内容，则返回默认值（在这种情况下为None）：

detail = "this is not active"
inactive = next((term for term in phrase if term in detail), None)
if inactive:
    print('matched phrase' + inactive)

如何获取匹配的字符串

2 个答案: