Question

我通过服务在Android应用程序中从我的服务器获取JSONObject，为了发送到我的活动，我将JSONObject转换为带有

的字符串

String myjson= gson.toJson(object);
b.putString("json", myjson);

将字符串传递给我的活动，我从String重新创建JSONObject

Gson gson = new Gson();
JSONObject jobj = gson.fromJson(mydata, JSONObject.class);
JSONArray jarray = jobj.getJSONArray("myitems");

我的JSON如下

{"myitems":[{"event_id":"1","title":"Music launch party at makeover","description":"Music Launch function at Makeover","store_id":"2","user_id":"1","category_id":"1","submittedby":"store","start_date":"2015-02-03 09:00:01","end_date":"2015-02-03 20:00:00","price":"1000","gallery_1":"","gallery_2":"","gallery_3":"","add_lat":"30.693771","add_lon":"76.76486","distance":"10.329089177806534"},{"event_id":"2","title":"The Bacardi party at the New year bash","description":"Altius organizes a new year bash at their Night House.","store_id":"2","user_id":"1","category_id":"3","submittedby":"user","start_date":"2015-02-05 17:08:40","end_date":"2015-02-05 22:08:48","price":"2000","gallery_1":"","gallery_2":"","gallery_3":"","add_lat":"30.69461","add_lon":"76.76176","distance":"10.575941394542852"}]}

但是我从jsonobject获取jsonarray时遇到错误。什么应该是从jsonobject获取jsonarray的正确方法，或者我在这里做错了什么。

Answer 1

尝试以下方法：

创建一个包含json对象副本的类

public class MyItem {

String event_id;
String title;
String description;
String store_id ;
String user_id;
String category_id;
String submittedby;
String start_date;
String end_date;
String price;
String gallery_1;
String gallery_2;
String gallery_3;
String add_lat;
String add_lon;
String distance;

public MyItem() {
}
}

在你的情况下，myjson是包含json reply..so

的字符串

        JSONArray array = null;

        try {
            JSONObject jsonResp = new JSONObject(myjson);
            array = jsonResp.getJSONArray("myitems");

        } catch (JSONException e) {

            e.printStackTrace();
        }

然后你可以遍历数组并在自定义类中存储对象，如下所示：

for（int i = 0; i＆lt; array.length（）; i ++）{ JSONObject json2 = null;

    try {
           json2 = (JSONObject) array.get(i);
        } catch (JSONException e) {
           e.printStackTrace();
        }

    Gson gson = new Gson();
    MyItem myItem = gson.fromJson(json2.toString(), MyItem.class);


    //Do whatever you want with the object here

}

转换为JSONArray时出现JSONException

1 个答案: