通过I2C提供16x2 LCD的Python代码可提供替代结果

Question

我试图使用一些Python代码在16x2 LCD显示屏上显示文字（＆＃34;兼容＆＃34;与经典Hitachi HD44780）通过I2C连接到RaspberryPi B +型号＆＃34;返回-pack＆＃34 ;.

此I2C板具有PCF8574 IC。

这是图书馆（归属于RaspberryPi forum，依次来自this blog post）：

import smbus
from time import *

# General i2c device class so that other devices can be added easily
class i2c_device:
 def __init__(self, addr, port):
  self.addr = addr
  self.bus = smbus.SMBus(port)

 def write(self, byte):
  self.bus.write_byte(self.addr, byte)

 def read(self):
  return self.bus.read_byte(self.addr)

 def read_nbytes_data(self, data, n): # For sequential reads > 1 byte
  return self.bus.read_i2c_block_data(self.addr, data, n)


class lcd:
 #initializes objects and lcd
 '''
 Port definitions
 addr, en,rw,rs,d4,d5,d6,d7,bl
 0x27, 2, 1, 0, 4, 5, 6, 7, 3
 '''
 def __init__(self, addr, port):
  self.lcd_device = i2c_device(addr, port)
  self.backlight=1; #default backlight on

  #set 4 bit mode
  self.lcd_device_writebl(0x20)
  self.lcd_strobe()
  sleep(0.0005)
  self.lcd_strobe()
  sleep(0.0005)
  self.lcd_strobe()
  sleep(0.0005)

  self.lcd_write(0x28)
  self.lcd_write(0x08)
  self.lcd_write(0x01)
  self.lcd_write(0x06)
  self.lcd_write(0x0C)
  self.lcd_write(0x0F)

#wrapper to self.lcd_device.write for backlight control
 def lcd_device_writebl(self,value):
  if self.backlight:
   self.lcd_device.write(value | 0x08);
  else:
   self.lcd_device.write(value)

# control backlight on=1 or off=0
 def lcd_backlight(self,on):
  self.backlight=on
  self.lcd_strobe()

 # clocks EN to latch command
 def lcd_strobe(self):
 #bit 2
  self.lcd_device_writebl((self.lcd_device.read() | 0x04))
  self.lcd_device_writebl((self.lcd_device.read() & 0xFB))

 # write a command to lcd
 def lcd_write(self, cmd):
  self.lcd_device_writebl((cmd >> 4)<<4)
  self.lcd_strobe()
  self.lcd_device_writebl((cmd & 0x0F)<<4)
  self.lcd_strobe()
  self.lcd_device_writebl(0x0)

 # write a character to lcd (or character rom)
 def lcd_write_char(self, charvalue):
   self.lcd_device_writebl((0x01 | (charvalue >> 4)<<4))
   self.lcd_strobe()
   self.lcd_device_writebl((0x01 | (charvalue & 0x0F)<<4))
   self.lcd_strobe()
   self.lcd_device_writebl(0x0)

 # put char function
 def lcd_putc(self, char):
  self.lcd_write_char(ord(char))

 # put string function
 def lcd_puts(self, string, line):
  if line == 1:
   self.lcd_write(0x80)
  if line == 2:
   self.lcd_write(0xC0)
  if line == 3:
   self.lcd_write(0x94)
  if line == 4:
   self.lcd_write(0xD4)

  for char in string:
   self.lcd_putc(char)

 # clear lcd and set to home
 def lcd_clear(self):
  self.lcd_write(0x1)
  self.lcd_write(0x2)

 # add custom characters (0 - 7)
 def lcd_load_custon_chars(self, fontdata):
  self.lcd_device.bus.write(0x40);
  for char in fontdata:
   for line in char:
    self.lcd_write_char(line)

和测试代码：

import time
import pylcdlib

lcd = pylcdlib.lcd(0x27,1)

lcd.lcd_puts("Hello",1) #display "Hello" on line 1
lcd.lcd_puts("World!",2) #display "World!" on line 2

time.sleep(1)
lcd.lcd_clear()

问题是这个示例代码按顺序运行多次，一次运行正常，下一次LCD显示随机字符;再一次，一个好，一个错。

有谁知道为什么？我是Python的初学者，我搜索了很多但没有结果。

感谢。

编辑：实际上，重复该行

lcd = pylcdlib.lcd(0x27,1)
lcd = pylcdlib.lcd(0x27,1)

让脚本每次都运行良好，但它没有意义（好吧，我确定它确实如此，但我不知道为什么）。