Question

我想比较行结果，并在特定列具有相同的fightID时创建新列。

我的查询：

SELECT fight.fightdato, fight.fightID, players.name, 
       playersfight.playerid, playersfight.playerScore 
FROM fight 
INNER JOIN playersfight ON fight.fightID = playersfight.fightID 
INNER JOIN players ON playersfight.playerID = players.playersID

导致php：

Fight   Fight Date  Player  PlayerScore
1       2014-10-10  Kevin   8
1       2014-10-10  Chris   4
2       2014-09-01  Kevin   8
2       2014-09-01  Eric    4

我想要的结果：

Fight   Fight Date Player1 Result1 Player2 Result2
1       2014-10-10 Kevin   8       Chris   4
2       2014-09-01 Kevin   8       Eric    4

btw - 我是php / mysql和一般编程的新手

感谢您的帮助！

Answer 1

您需要再次加入player和playerfight表格。

类似的东西：

SELECT fight.fightID, fight.fightdato,
       p1.name as 'Player_1', pf1.playerid as 'PlayerID_1', pf1.playerScore as 'Result_1',
       p2.name as 'Player_2', pf2.playerid as 'PlayerID_2', pf2.playerScore as 'Result_2'          
FROM fight 
JOIN playersfight pf1 ON fight.fightID = pf1.fightID 
JOIN players p1       ON pf1.playerID  = p1.playersID
JOIN playersfight pf2 ON fight.fightID = pf2.fightID 
JOIN players p2       ON pf2.playerID  = p2.playersID
WHERE p1.playersID < p2.players2

带有WHERE条件的p1.playersID < p2.players2子句排除了我们不希望返回的两种情况：

结果连续两次加入同一个玩家。
重复 - 例如，对于ID为1和2的玩家，会有两次玩家ID (1,2)和(2,1)同一回合。现在它只返回第一个排列。

比较行结果并创建新列

1 个答案: