Question

我有一串HTML需要抓取“[Title | http://www.test.com]”模式，例如

“dafasdfasdf，adfasd。[测试| http://www.test.com/] adf ddasfasdf [SDAF | http://www.madee.com/] assg ad”

我需要将“[Title | http://www.test.com]”替换为“http://www.test.com/'>Title”。

最好的办法是什么？

我接近了：

string test = "dafasdfasdf adfasd [Test|http://www.test.com/] adf ddasfasdf [SDAF|http://www.madee.com/] assg ad ";
        string p18 = @"(\[.*?|.*?\])";
        MatchCollection mc18 = Regex.Matches(test, p18, RegexOptions.Singleline | RegexOptions.IgnoreCase);
        foreach (Match m in mc18)
        {
            string value = m.Groups[1].Value;
            string fulltag = value.Substring(value.IndexOf("["), value.Length - value.IndexOf("["));
            Console.WriteLine("text=" + fulltag);
        }

必须有一种更清晰的方法来获取两个值，例如“标题”位和网址本身。

有什么建议吗？

Answer 1

替换模式：

\[([^|]+)\|[^]]*]

使用：

$1

一个简短的解释：

\[         # match the character '['
(          # start capture group 1
  [^|]+    #   match any character except '|' and repeat it one or more times
)          # end capture group 1
\|         # match the character '|'
[^]]*      # match any character except ']' and repeat it zero or more times
]          # match the character ']'

C＃演示看起来像：

string test = "dafasdfasdf adfasd [Test|http://www.test.com/] adf ddasfasdf [SDAF|http://www.madee.com/] assg ad ";
string adjusted = Regex.Replace(test, @"\[([^|]+)\|[^]]*]", "$1");

RegEx替换查询以挑选wiki语法

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