如何停止此循环语句

时间:2015-02-10 03:58:50

标签: java loops

我想要一个代码,告诉你输入两个数字,直到你输入两个偶数倍的数字。我正在为这个任务使用一个循环语句,当我运行我的代码并输入两个不是偶数的数字时,它会一直说"请输入偶数倍数"。请帮我。 Thx提前。这是我的代码。

public class looper {
      public static void main (String[] args) {

     float firstNumber = 0;
     float secondNumber = 0;   
     float finalNumber = 0;

     java.util.Scanner input=new java.util.Scanner(System.in);

     System.out.println("Enter your first number."); 
        firstNumber = input.nextFloat();
        input.nextLine();


        System.out.println("Enter your second number."); 
        secondNumber = input.nextFloat();

         finalNumber = firstNumber % secondNumber;

         System.out.println(secondNumber + " and " + firstNumber + " are even multiples.");
     while(finalNumber != 0) { 

        System.out.println("Please enter even multiples.");


        }
      }
    }

4 个答案:

答案 0 :(得分:0)

您需要设置finalNumber的值,使其满足while循环的终止条件。你可能想做这样的事情(我没有编译这段代码!):

while (finalNumber != 0){

    System.out.println("Enter your first number."); 
    firstNumber = input.nextFloat();
    input.nextLine();

    System.out.println("Enter your second number."); 
    secondNumber = input.nextFloat();

    finalNumber = firstNumber % secondNumber;

}
System.out.println(secondNumber + " and " + firstNumber + " are even multiples.");  

答案 1 :(得分:0)

在计算while循环的条件时要小心。如果不更新用于检查循环内部的变量,则会进入无限循环。

这里重要的是你需要用户提供两个值。你根本不需要第三个变量来跟踪它,这取决于你如何写它,但它可以用这种方式编写:

  • 获得价值#1
  • 获得价值#2
  • 虽然value1 % value2 == 0 ...
    • ...再次打印消息并从用户检索值#1和值#2。
  • 打印完成消息。
System.out.println("Enter your first number."); 
firstNumber = input.nextFloat();
input.nextLine();
System.out.println("Enter your second number."); 
secondNumber = input.nextFloat();

while(firstNumber % secondNumber != 0) {
    System.out.println("Please enter two numbers that are multiples of each other.");
    System.out.println("Enter your first number."); 
    firstNumber = input.nextFloat();
    input.nextLine();
    System.out.println("Enter your second number."); 
    secondNumber = input.nextFloat();
}

// afterwards, print whatever message you require.

答案 2 :(得分:0)

如果你没有使用的问题,那么使用if条件。制作两个独立的功能。一种是检查调用其他条件的条件以获得结果。这是一个示例代码。希望,它会帮助你。对不起,可能是英语不好。

public class Looper 
{
      public static void main (String[] args) 
      {
          Looper looper = new Looper();
          looper.runTest();
      }

      public void runTest()
      {
          float finalNumber = getResult();
          System.out.println("finalNumber: " + finalNumber);
          if(finalNumber != 0.0) 
         { 
            System.out.println("Please enter even multiples.");
            runTest();
         }
      }

      public float getResult()
      { 
          java.util.Scanner input=new java.util.Scanner(System.in);

          System.out.println("Enter your first number."); 
          float firstNumber = input.nextFloat();
          input.nextLine();

          System.out.println("Enter your second number."); 
          float secondNumber = input.nextFloat();
          float finalNumber = firstNumber % secondNumber;
          System.out.println(secondNumber + " and " + firstNumber + " are even multiples.");
          return finalNumber;
      }

    }

答案 3 :(得分:-1)

您需要使用if语句,因为您只想告知用户输入的数字不正确

do{
    System.out.println("Enter your first number."); 
    firstNumber = input.nextFloat();
    input.nextLine();


    System.out.println("Enter your second number."); 
    secondNumber = input.nextFloat();

    finalNumber = firstNumber % secondNumber;
    if(finalNumber!=0)
        System.out.println("values not correct ");
}while(finalNumber!=0);
相关问题