Question

所以我有2个查询，其中一个是使用第一个查询中的值的子查询。我需要将它变成1个查询，以便我可以将它们作为视图。所以第一个查询是，

    SELECT LEVEL WEEK_NUM_INCR,
           TO_CHAR (start_date + (LEVEL - 1) * 7, 'DD-MON-YYYY') START_WEEK_DATE,
           TO_CHAR (start_date + (LEVEL) * 7, 'DD-MON-YYYY') END_WEEK_DATE 
      FROM (SELECT PS.PROJECT_START_DT start_date,
                   PS.JOB_NAME JOB_NAME,
                   PS.PROJECT_END_DT end_date
              FROM PROJECT_SPAN PS
             WHERE PS.JOB_NAME = :JOBNAME) RS
CONNECT BY start_date + (LEVEL - 1) * 7 < end_date;

，第二个查询是，

  SELECT SUM (DO.ONSITE_UPD_QTY) ONSITESUM,
         SUM (DO.ONSITE_UPD_QTY * MD.WEIGHT) TOTALONSITEWEIGHT,
    FROM PROJECT P
         LEFT OUTER JOIN DTL_ERC_UPD@WELTES_SITEMON_LINK DO
            ON DO.PROJECT_NAME = P.PROJECT_NAME
         LEFT OUTER JOIN MASTER_DRAWING MD ON MD.HEAD_MARK = DO.HEAD_MARK
   WHERE     DO.UPD_DATE BETWEEN TO_DATE (:STARTDATE, 'DD-MON-YYYY')
                             AND TO_DATE (:ENDDATE, 'DD-MON-YYYY')
         AND P.PROJECT_NO = :PROJNO
GROUP BY P.PROJECT_NO;

第二个查询使用第一个查询START_WEEK_DATE和END_WEEK_DATE中的值：STARTDATE和：ENDDATE作为第一个查询中特定日期范围的范围值。

因此可以在http://pastie.org/9938791中看到php中的整个方法但是将它们组合在一起并在JSON中分配值是不可能的。请帮我组合这两个查询..我真的很感激

Answer 1

您可以使用WITH-Clause将第一个查询用作子查询：

http://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_10002.htm

WITH JOBNAME AS (1stQuery)
SELECT-CLAUSE USING JOBNAME as Inlineview (in the FROM-Condition).

e.g。 http://oracle-base.com/articles/misc/with-clause.php

将2个ORACLE查询组合成1个查询

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