Question

我必须发送包含参数'username'和'password'的POST请求。

我相信我在下面这样做了：

public static void execute() {
    Map<String, String> comment = new HashMap<String, String>();
    comment.put("username", login.getText().toString());
    comment.put("password", password.getText().toString());
    String json = new GsonBuilder().create().toJson(comment, Map.class);
    makeRequest("http://www.example.com", json);
}

public static HttpResponse makeRequest(String uri, String json) {
    try {
        HttpPost httpPost = new HttpPost(uri);
        httpPost.setEntity(new StringEntity(json));
        httpPost.setHeader("Accept", "application/json");
        httpPost.setHeader("Content-type", "application/json");
        Log.d("Result", httpPost.toString());
        return new DefaultHttpClient().execute(httpPost);
    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return null;
}

下一步说我将收到一个带有“id”和“验证”的JSON响应。如何显示/解析此JSON响应？我试过做`Log.d（“Result”，httpPost.toString（））;但这显然不起作用，我不知道我在这做什么。

有人可以帮忙吗？

Answer 1

调用DefaultHttpClient().execute后，从服务器读取响应：

HttpResponse  response=makeRequest("http://www.example.com", json);
BufferedReader reader = new BufferedReader(
          new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
StringBuilder builder = new StringBuilder();
for (String line = null; (line = reader.readLine()) != null;) {
    builder.append(line);
}

Log.d("Result","Response :: "+ builder.toString());

如果服务器返回JSON响应然后将builder.toString()转换为JSONObject并使用键从中获取所有值

显示POST请求的JSON响应

1 个答案: