PHP表单获取和后输出使用If语句在同一页面上输出结果

时间:2015-02-16 02:34:29

标签: php forms post if-statement get

我现在正在学习PHP和处理表单。我有一个任务是在同一页面上创建一个表单,一个GET和一个POST,并将结果发布在每个表单下面的同一页面上。

我创建了一个if / else语句,但也许我错误地解决了这个问题。

<div>
<h1>POST Method Form</h1>
<form  method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>" >
First Name:<br>
<input type="text" name="firstname"><br>
Last Name:<br>
<input type="text" name="lastname"><br>
E-mail: <input type="text" name="email"><br>
Database Utilized:  <br>
<input type="checkbox" name="dba" value="SQL Server">SQL Server<br>
<input type="checkbox" name="dba" value="Oracle">Oracle<br>
<input type="checkbox" name="dba" value="Access">Microsoft Access<br>
<br>
<input type="submit" name="postsubmit" value="Submit">
</form>
<br>
<h1>Database Consulting POST Form Results</h1>
<p>
<?php
if (isset($_POST['postsubmit'])) {

    $firstname = $_POST['firstname'];
    $lastname = $_POST['laststname'];
    $email = $_POST['email'];
    $dba = $_POST['dba'];
    echo $firstname; <br>
    echo $lastname; <br>
    echo $email; <br>
    echo $dba; <br>
}

else {
     echo "Please enter correct values in form and hit submit";
}

?>
</p>

<br>
<h1>GET Method Form</h1>
<form method="GET" action="<?php echo $_SERVER['PHP_SELF']; ?>" >
First name:<br>
<input type="text" name="firstname_get"><br>
Last name:<br>
<input type="text" name="lastname_get"><br>
E-mail: <input type="text" name="email_get"><br>
Database Utilized<br>
<input type="checkbox" name="dba_get" value="SQL Server">SQL Server<br>
<input type="checkbox" name="dba_get" value="Oracle">Oracle<br>
<input type="checkbox" name="dba_get" value="Access">Microsoft Access<br>
<br>
<input type="submit" name="getsubmit" value="Submit">
</form>
<br>
<br>
<h1>Database Consulting GET Form Results</h1>

<p>

<?php 
if (isset($_GET['getsubmit'])) {
    $firstname_get = $_GET['firstname'];
    $lastname_get = $_GET['laststname'];
    $email_get = $_GET['email'];
    $dba_get = $_GET['dba'];
    echo $firstname_get; <br>
    echo $lastname_get; <br>
    echo $email_get; <br>
    echo $dba_get; <br>
}

else {
     echo "Please enter correct values in form and hit submit";
}

?>
</p>

</div>

2 个答案:

答案 0 :(得分:4)

您将$_GET['lastname']拼错为$_GET['laststname'],将您的操作更改为action="",并将您的<br>添加到回复语句中,例如echo $firstname .'<br>';而不是echo $firstname; <br> }

<h1>POST Method Form</h1>
 <form  method="POST" action="" >
  First Name:<br>
<input type="text" name="firstname"><br>
Last Name:<br>
 <input type="text" name="lastname"><br>
 E-mail: <input type="text" name="email"><br>
  Database Utilized:  <br>
 <input type="checkbox" name="dba[]" value="SQL Server">SQL Server<br>
 <input type="checkbox" name="dba[]" value="Oracle">Oracle<br>
 <input type="checkbox" name="dba[]" value="Access">Microsoft Access<br>
  <br>
 <input type="submit" name="postsubmit" value="Submit">
 </form>
  <br>
  <h1>Database Consulting POST Form Results</h1>
 <p>
  <?php
 if (isset($_POST['postsubmit'])) {

$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$email = $_POST['email'];
$dba = $_POST['dba'];
echo $firstname .'<br>';
echo $lastname .'<br>';
echo $email .'<br>';
foreach ($dba as $database) {
    echo $database .'<br>';
}
}

 else {
 echo "Please enter correct values in form and hit submit";
 }

 ?>
 </p>

答案 1 :(得分:-1)

首先,我建议有一个名为action的隐藏字段:

<input type="hidden" name="action" value="submituserinfo" />

然后把你的php逻辑放在顶部而不是底部,在页面显示之前进行处理!你的PHP_SELF交易很好。但你的逻辑是关闭的。正确的逻辑应该是:

if(isset($_REQUEST['action']) && $_REQUEST['action']=='submituserinfo'){
    //analyze the data

    if($errors){
        //set a var to show errors below
    }else{
        //enter the data, whatever
    }
}

这应该让你开始朝着正确的方向前进。如果将编码放在文档的头部,则可以更好地处理输出,甚至可以根据成功或错误使用header()进行重定向。