Question

我想阅读以下xml文件格式：

<?xml version="1.0" encoding="ISO-8859-1"?>
<WIDECAST_DVB>
  <channel name="XXX">
    <event id="0" start_time="2015-01-27 14:00:00" duration="28800">
      <short_event_descriptor lang="alb" name="Edicion informativ">Lajme nga vendi dhe bota</short_event_descriptor>
      <extended_event_descriptor lang="alb">
        <text />
      </extended_event_descriptor>
    </event>
    <event id="1" start_time="2015-01-27 22:00:00" duration="28800">
      <short_event_descriptor lang="alb" name="Edicion informativ">Lajme nga vendi dhe bota</short_event_descriptor>
      <extended_event_descriptor lang="alb">
        <text>jchdvdgd 
        </text>
      </extended_event_descriptor>
    </event>
    <event id="2" start_time="2015-01-28 06:00:00" duration="28800">
      <short_event_descriptor lang="alb" name="Edicion informativ">Lajme nga vendi dhe bota</short_event_descriptor>
      <extended_event_descriptor lang="alb">
        <text />
      </extended_event_descriptor>
    </event>
    <event id="3" start_time="2015-01-28 14:00:00" duration="28800">
      <short_event_descriptor lang="alb" name="Edicion informativ">Lajme nga vendi dhe bota</short_event_descriptor>
      <extended_event_descriptor lang="alb">
        <text />
      </extended_event_descriptor>
    </event>
 </channel>
</WIDECAST_DVB>

我想阅读这些字段：

名，开始时间，持续时间，短事件descriptor_name，短事件描述（标签内的文字）， extended_event_descriptor / text（文本标记内的文本）

我的课程是：

 public class epg2
    {
        public epg2()
        {
            EventNumber = new List<Event>();
        }
        virtual public string channelname { get; set; }
        virtual public List<Event> EventNumber { get; set; }
        virtual public int number { get; set; }

    }
    public class Event
    {
        public Event()
        {

        }
        virtual public DateTime starttime { get; set; }
        virtual public int duration { get; set; }
        virtual public string name { get; set; }
        virtual public string shortDescription { get; set; }
        virtual public string longDescription { get; set; }

    }

Answer 1

以LinqToXML为例：

XDocument doc = XDocument.Parse(xml);

        var resultChannels =
            doc.Descendants("channel")
                .Select(
                        c =>
                            new epg2()
                            {
                                channelname = c.Attribute("name").Value,
                                EventNumber =
                                    c.Elements("event")
                                    .Select(e =>
                                    new Event()
                                    {
                                        name = e.Element("short_event_descriptor").Attribute("name").Value,
                                        starttime = DateTime.Parse(e.Attribute("start_time").Value),
                                        duration = int.Parse(e.Attribute("duration").Value),
                                        shortDescription = e.Element("short_event_descriptor").Value,
                                        longDescription = e.Element("extended_event_descriptor").Element("text").Value
                                    }).ToList()
                            }).ToList();

asp.net中的xml阅读器c＃

1 个答案: