Question

我正在尝试使用 containsLocation 选项计算2个多边形的公共字段，以使大量相同的小字段仅放置在公共字段中。我认为 containsLocation（ this ，pole1）有问题。我尝试了许多其他方法，仍然没有工作。如果你已经知道如何计算复杂的多边形公共字段，你也可以在这里写下来。

问题

var x,y,countmarkers;countmarkers=0;
for(x=52.8;x<=54;x=x+0.15){
    for(y=12.6;y<=19;y=y+0.25) {

        var point = { lat: x, lng: y};
        if (google.maps.geometry.poly.containsLocation(point, pole1)) {
             if (google.maps.geometry.poly.containsLocation(point, pole2)){
                var marker = new google.maps.Marker({
                     position: new google.maps.LatLng(x, y),
                     map: map
                 });
                 countmarkers++;
            }
        }
    }
}

完整代码

var map;
function initialize() {
  var mapOptions = {
      mapTypeId: google.maps.MapTypeId.TERRAIN,
      center: {lat: 52.597060, lng: 18.516048},
      zoom: 6
  };

    var map = new google.maps.Map(document.getElementById('map-canvas'),mapOptions);
    var pole0;
    pole0 = [
        [
         new google.maps.LatLng(54, 14),
         new google.maps.LatLng(53, 14),
         new google.maps.LatLng(53, 15),
         new google.maps.LatLng(54, 15)],
        [
            new google.maps.LatLng(54, 15),
            new google.maps.LatLng(53, 13),
            new google.maps.LatLng(53, 17),
            new google.maps.LatLng(54, 17)]
    ];
    var pole2,pole1;
    pole1 = new google.maps.Polygon({
        //map: map,
        paths: pole0[0],
        strokeColor: '#000000',
        strokeWeight: 4,
        strokeOpacity: 1,
        fillColor: '#ff0000',
        fillOpacity: 0.5
    });
    pole2 = new google.maps.Polygon({
        //map: map,
        paths: pole0[1],
        strokeColor: '#ffffff',
        strokeWeight: 4,
        strokeOpacity: 1,
        fillColor: '#ff0000',
        fillOpacity: 0.5
    });


var x,y,countmarkers;countmarkers=0;
for(x=52.8;x<=54;x=x+0.15){
    for(y=12.6;y<=19;y=y+0.25) {

        var point = { lat: x, lng: y};
        if (google.maps.geometry.poly.containsLocation(point, pole1)) {
             if (google.maps.geometry.poly.containsLocation(point, pole2)){
                var marker = new google.maps.Marker({
                     position: new google.maps.LatLng(x, y),
                     map: map
                 });
                 countmarkers++;
                }
            }
        }
    }

//if you comment "problem" part of code & "map: map" in polygon declarations, 
//this listener will work well, placing markers only in polygon "pole1"
    google.maps.event.addListener(map, 'click', function(e) {
        if (google.maps.geometry.poly.containsLocation(e.latLng, pole1)) {
            var marker = new google.maps.Marker({
                position: e.latLng,
                map: map
            });
        }

    });
}

google.maps.event.addDomListener(window, 'load', initialize);

Answer 1

var x,y,countmarkers=0;
for(x=52.8;x<=54;x=x+0.15){
    for(y=12.6;y<=19;y=y+0.25) {

        var point = new google.maps.LatLng(x,y);
        if (google.maps.geometry.poly.containsLocation(point, pole1)) {
             if (google.maps.geometry.poly.containsLocation(point, pole2)){
                var marker = new google.maps.Marker({
                     position: point,
                     map: map
                 });
                 countmarkers++;
                }
            }
        }
    }

包含与循环和放大器的位置合作共同领域

1 个答案: