提交ajax-php联系表单后 - 打开弹出消息的bootstrap模式

Question

我想要显示这种按摩＆＃34;谢谢！＆＃34;通过bootstrap模态而不是警报。

//AJAX code to submit form.
$.ajax({
        type: "POST",
        url: "ajaxsubmit.php",
        data: dataString,
        cache: false,
        success: function(result){
                            alert("Thank you!");
                                }
});

Answer 1

给你的模态一个id类似“ thankyouModal ”，ref creating modal

$.ajax({
        type: "POST",
        url: "ajaxsubmit.php",
        data: dataString,
        cache: false,
        success: function(result){
                            $("#thankyouModal").modal('show')
                                }
});