Question

我有一个python代码，试图通过询问一些问题来猜测用户的年龄。问题是，当用户的年龄等于变量时，while循环不会中断。这是我的代码：

age = 50
guess = raw_input("Give your age: ")
while guess != age:
  print "Are you above ",age,"?"
  x = raw_input()
  while (x != "yes") and (x != "YES") and (x != "no") and (x != "NO"):
    print "Answer with yes/YES, no/NO"
    x = raw_input()
  if (x == "yes") or (x == "YES"):
    age = 2*age-age/2
  else:
    age = age/2

  if age == guess:
    break

print "Your age is ",age

Answer 1

您需要转换为int，raw_input会返回一个字符串，因此您要将string与int进行比较，而guess = int(raw_input("Give your age: ")) age == guess: ^^ ^^^ int str永远不会评估为True：

in

不确定代码的其余部分是做什么的，但您可以使用while x not in {"yes","YES","no", "NO"}:来替换＆＃39>：

if  x == "yes" or x == "YES":

哟在你的if语句中也不需要parens：

{{1}}

Answer 2

每次循环时都必须定义中断条件。

在您的代码中，您只需定义guess一次。所以它的价值不会改变。

请在while循环中添加guess，以便更改其值，您将达到中断状态。

Answer 3

最好改变无限迭代的条件。

# while guess != age:
while True:

当条件满足时，循环不会中断

3 个答案: