使用ravendb和.net客户端删除重复的文档

Question

我使用map reduce创建了一个索引来查找重复项，并且我成功找到了重复项。这是我的班级

class Employee {
public string Name {get; set;}
public string address {get; set;}
public string email {get; set;}
}

使用map reduce，我的结果是这样的

Sal abc salo@yahoo.co 2

此处，数据表明有2个重复文件。现在我的问题是我必须删除其中一个文件。显然，通过这种方式，我无法获取文档ID，因为我无法按文档ID进行分组。那么在找到重复项以删除其中一个文档后，我该怎么办？

以下是map reduce

的代码

namespace DuplicateEmployee.Storage.Indexes
{

    public class DupEmployeeIndex : AbstractIndexCreationTask<Employee, DupEmployeeIndex.UniqueEmployeeResult>
    {

        public class UniqueEmployeeResult
        {
            public string LastName { get; set; }
            public string FirstName { get; set; }

            public string address1 { get; set; }

            public string address2 { get; set; }
            public string city { get; set; }
            public string state { get; set; }

            public string zip { get; set; }



            public string DOB { get; set; }
            public int Count { get; set; }
        }
        public DupEmployeeIndex()
        {
            Map = employees => from employee in employees
                              select
                               new
                               {
                                  LastName = employee.LastName,
                                  FirstName = employee.FirstName,
                                  address1 = employee.Address1,
                                  address2 = employee.Address2,
                                  city = employee.City,
                                  state = employee.State,
                                  zip = employee.Zip,
                                  DOB = employee.DateOfBirth,
                                  Count = 1
                               };

            Reduce = results => from result in results                         
                                group result by new { result.LastName,
                                    result.FirstName,
                                    result.address1,
                                    result.address2,
                                    result.city,
                                    result.state,
                                    result.zip,
                                    result.DOB

                                   }
                                    into g   

                                select new

                                {

                                    LastName = g.Key.LastName,

                                   FirstName = g.Key.FirstName,
                                  address1 = g.Key.address1,
                                  address2 = g.Key.address2,
                                  city = g.Key.city,
                                  state = g.Key.state,
                                  zip = g.Key.zip,
                                  DOB = g.Key.DOB,
                                    Count = g.Sum(x => x.Count)

                                };
        }
    }
}