显示保龄球得分的最高平均值

时间:2015-02-24 18:00:40

标签: java

我无法让代码显示四个平均值的最高平均值,我似乎只得到最后的平均分数,并且填写了最高的平均值,这不是最高分。

这是我的代码:

 import java.io.*;
    import java.util.*;

    class Bowling Scores
    {

    public static void main (String args[])

    {
      Scanner keyboard = new Scanner(System.in);
       int G =0;
       int scores = 0;
       double avg = 0;
       double highest_average=0;
       int times = 0;
       int players = 4;

      for(int i =1; i<=players; i++) {
         System.out.println("Player " + i);
          if (avg > highest_average) 
            highest_average= avg; 
              do
         {
            System.out.println("Enter your bowling score:");
            G = keyboard.nextInt();
            scores += G;
            times++;
         }
         while((G !=-1));  // -1 is what makes the loop end for the current player, a total of four players will get an average after -1 is inputted
         scores += + 1;
         times = times - 1; 
         avg = (scores)/(times);
         System.out.printf("Average= %.2f\n", avg);
         scores =0; times =0; 
         System.out.println("");
      }

         System.out.println("Highest average:" + highest_average);

     }

    }

以下是代码的示例运行:

 Player 1

 Enter your bowling score:

 300

 Enter your bowling score:

 222

 Enter your bowling score:

 -1

 Average= 261.00

 Player 2

 Enter your bowling score:

 210

 Enter your bowling score:

 211

 Enter your bowling score:

 300

 Enter your bowling score:

 -1

 Average= 240.00

 Player 3

 Enter your bowling score:

 233

 Enter your bowling score:

 -1

 Average= 233.00

 Player 4
 Enter your bowling score:

 112

 Enter your bowling score:

 -1

 Average= 112.00

 Highest average:112.0 // this is not the highest score.

2 个答案:

答案 0 :(得分:1)

您永远不会为每位玩家更新最高平均值,仅适用于最后一位玩家。这就是为什么你总是使用最后一个人的平均值。

只需在for循环中移动你的if语句,它应该可以正常工作。确保将print语句保留在循环外部,以便最后只打印一次最高平均值。

for (int i = 1; i <= players; i++) {
    System.out.println("Player " + i);
    do {
        System.out.println("Enter your bowling score:");
        G = keyboard.nextInt();
        scores += G;
        times++;
    } while ((G != -1)); // -1 is what makes the loop end for the current player, a total of four players will get an average after -1 is inputted

    scores += +1;
    times = times - 1;
    avg = (scores) / (times);
    System.out.printf("Average= %.2f\n", avg);
    scores = 0;
    times = 0;
    System.out.println("");

    if (avg > highest_average) {
        highest_average = avg;
    }
}
System.out.println("Highest average:" + highest_average);

答案 1 :(得分:1)

if (avg > highest_average) {           
     highest_average= avg;

此代码应位于for循环中,否则最高平均值永远不会更新。

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