Question

堆垛，当用SQL语法编写时，我一直在努力理解PIVOT ......

我的数据格式：

CONTID  STCODE
8203    BA
8203    BA
8203    UY
8203    UY
8203    UY
8203    FA
8203    FA
8203    FA
8203    UY
8203    UY
8203    *LC
8203    *LC
8203    *LC
8203    UY

预期输出：

CONTID   BA    *LC    UY    FA
8203     2     3      6     3

到目前为止我的可怕尝试......（我不知道在括号或SELECT子句中放什么。

SELECT c.CONTID, [STCODE] AS 'Burglary Alarm', [STCODE] AS 'Late-to-close'
FROM CUSTOMER c LEFT JOIN CLOGS15 h ON c.SERIALNO = h.SERIALNO 
PIVOT
(
SUM(h.STCODE)
FOR h.STCODE 
IN ([BA], [*LC])
) AS pvt

Answer 1

试试这个

SELECT 
CONTID,
[BA] AS 'Burglary Alarm', 
[*LC] AS 'Late-to-close', 
[UY], 
[FA]
FROM 
(
  SELECT c.CONTID, 
  [STCODE]
  FROM CUSTOMER c 
  LEFT JOIN CLOGS15 h ON c.SERIALNO = h.SERIALNO 
  WHERE C.CONTID LIKE '8203' AND h.EVTYPE = 1 
  AND DATEADD(hour,-6,h.EVDATE) 
  BETWEEN '2015-02-23 06:30:00.000' AND '2015-02-24 06:30:00.000'
) SRC
PIVOT
(
  COUNT(SRC.STCODE)
  FOR SRC.STCODE IN ([BA], [*LC], [UY], [FA])
) AS pvt

SQL Pivot与SUM / Count结合使用

1 个答案: