当我已计算总行数时,如何计算mysql中的分组行数

时间:2015-02-25 18:01:44

标签: php mysql sql count distinct

我有下表,我想做以下事情:

  1. 计算每个项目在表格中显示的次数

  2. 计算DISTINCT件数

  3. 按名称对项目进行分组

    +-------+---------+
    |  id   |  names  |
    +-------+---------+
    |   1   |  Apple  |
    |   2   |  Orange | 
    |   3   |  Grape  | 
    |   4   |  Apple  | 
    |   5   |  Apple  | 
    |   6   |  Orange | 
    |   7   |  Apple  | 
    |   8   |  Grape  |  
    +-------+---------+
    

    对于1.和3.分,我有以下查询,它运作得很好:

    SELECT * , 
       COUNT(names) as count_name, 
       FROM tbl_products WHERE type = '1' 
       GROUP BY names
    

    所以我得到了:

    Apple  (4)
    Orange (2)
    Grape  (2)
    
  4. 现在我想计算按行分组的数量并添加一行来计算不同的元素,但是有一些问题,因为MySQL接受查询但不能输出结果:

    SELECT * , 
       COUNT(names) as count_name, 
       COUNT(DISTINCT names) as count_total 
       FROM tbl_products WHERE type = '1' 
       GROUP BY names
    

    有人可以建议可能出现的问题吗?

    编辑:为了获得更多许可,我想得到一张这样的表:

        +-------+---------+------------+-------------+
        |  id   |  names  |  count_ctg | count_total |
        +-------+---------+------------+-------------+
        |   1   |  Apple  |      4     |      3      |
        |   2   |  Orange |      2     |      3      |
        |   3   |  Grape  |      2     |      3      |
        +-------+---------+------------+-------------+
    

4 个答案:

答案 0 :(得分:1)

为什么不使用您正在使用的查询:

SELECT * , 
COUNT(names) as count_name, 
FROM tbl_products WHERE type = '1' 
GROUP BY names

此查询实现了所有三个目标。

1)您可以计算count_name中每个名称值的数量。

2)由于您按names分组,因此不同names值的数量将等于结果集中的行数。几乎任何客户端MySQL数据库连接库都可以让您检索此值。

3)您明确使用GROUP BY names

符合您的第三个按名称分组的标准

当然,结果集中id的值毫无意义,您可能只想选择namescount_names

答案 1 :(得分:0)

1 - 。计算每个项目出现在表格中的次数:

SELECT names, count(names) FROM tbl_products WHERE type = '1' group by names

2 - 。表中存在多少个不同的项目:

SELECT DISTINCT names FROM tbl_products WHERE type = '1'

3-。按名称对项目进行分组:

SELECT count(DISTINCT names) as Total FROM tbl_products WHERE type = '1'

作为你的最后一次编辑(ALL IN ONE):

SELECT id, names, count(names), total FROM tbl_products, (select count(distinct names) as total from tbl_products) as total WHERE type = '1' group by names

答案 2 :(得分:0)

您可以在子查询中获取不同名称的计数,然后将该东西连接到您已经为1和3解决的主查询中:

SELECT names , 
    COUNT(names) as count_name, 
    Total
FROM tbl_products 
    OUTER JOIN (SELECT count(DISTINCT names) as Total FROM tbl_products) t2 
WHERE type = '1' 
GROUP BY names

答案 3 :(得分:0)

您可以使用SQL Windowing OVER()

此查询返回row_number()函数作为结果中的id列,row_number的over(...)需要order by子句。你可以按照你想要的任何方式订购,但大部分都是按照订购的方式订购。

;WITH vwGroups (name, Quantity) AS 
(
    SELECT  name
    ,       COUNT(*)
    FROM    tbl_products
    GROUP BY name 
)
SELECT  ROW_NUMBER() OVER(ORDER BY Quantity DESC, name) AS id
,       name
,       Quantity AS count_name
,       COUNT(*) OVER () AS count_total
FROM    vwGroups