Laravel 4:尝试......抓不到工作

时间:2015-02-26 20:12:39

标签: laravel laravel-4 try-catch

我有一个类似的代码:

class ClassName extends BaseController implements InterfaceCrudController {
    public function FunctionName() {
        $error = null;
        $messenge = null;
        $request = Request::all();

        try {
            $query = DB::table("TableName")->where("Field_1", "=", $request["Field_1"])->where("Field_2", "=", $request["Field_2"]);

            $query->update(array(
                "Data_1" => $request["Data_1"],
                "Data_2" => $request["Data_2"]
            ));

            $error = false;
            $messenge = "Success";
        } catch (\Exception $e) {
            $error = true;
            $messenge = "Error: " . $e;
        }

        return Response::json(array(
            "error"  => $error,
            "messenge" => $messenge
        ));
    }
}

我遇到的问题是:当您运行 update()时,执行会停止并进入错误屏幕,显示“哎呀,看起来出了问题。” 我尝试了几件事,但我找不到让剧本向我显示例外的方法。

我该如何解决这个问题?

1 个答案:

答案 0 :(得分:0)

“哎呀,看起来出事了。”如果出现错误,页面是laravel将显示的默认视图。要获得有关错误的更多信息,包括堆栈跟踪,请执行以下操作,在app / config / app.php中打开调试模式:

/*
|--------------------------------------------------------------------------
| Application Debug Mode
|--------------------------------------------------------------------------
|
| When your application is in debug mode, detailed error messages with
| stack traces will be shown on every error that occurs within your
| application. If disabled, a simple generic error page is shown.
|
*/

'debug' => false,
相关问题