Question

我需要这样做，我想出了这个补充：

import random
mynos = []

print ("First, we'll do some addition")

for counter in range (0,2):
      mynumber = random.randint(1,20)
      mynos.append(mynumber)
print(mynos)

the_answer = sum(mynos)
#print(the_answer) (^^^)

player_answer =int(input("What is the answer?"))

def main():
      if player_answer is the_answer:
            print ("Correct! Well done!")
            print ("You scored 1 out of 10 so far!")
            print ("Good job!")
      else:
            print ("Incorrect! You scored null points!")
            print ("You have zero out of 10 so far!")
            exit()

main()

这是该计划的添加部分，但是没有使用sum来减去mynos中随机生成的两个数字吗？

Answer 1

如果你只有2个整数，只需对各个元素使用减法：

the_answer = mynos[0] - mynos[1]

＆＃39;功能性＆＃39;减去序列中数字的方法是使用reduce() function：

import operator
try:
    # Python 3 moved reduce to the functools module
    from functools import reduce
except ImportError:
    pass

the_answer = reduce(operator.sub, mynos)

在这种情况下，operator.sub() function代表-运营商。

生成两个随机数并减去它们

1 个答案: