Nodejs Sequelize没有插入

时间:2015-03-05 00:06:25

标签: javascript node.js sequelize.js

好吧,我现在已经盯着它看了2个小时,我根本找不到错误:

我有以下数据库表:

enter image description here

如果你不能告诉它有4列:

  • ID
  • 名称
  • 的organization_ID
  • competence_type_id

使用sequelize我使用以下代码:

var Competence = sequelize.define('competence', {
            id: DataTypes.INTEGER,
            name: DataTypes.STRING,
            organization_id: DataTypes.INTEGER,
            competence_type_id: DataTypes.INTEGER

        }, {
            freezeTableName: true,
            instanceMethods: {
                retrieveAll: function (org_id,onSuccess, onError) {
                    Location.findAll({where: {organization_id: org_id}}, {})
                        .ok(onSuccess).error(onError);
                },
                retrieveById: function (quote_id, onSuccess, onError) {
                    Location.find({where: {id: quote_id}}, {raw: true})
                        .success(onSuccess).error(onError);
                },
                add: function (onSuccess, onError) {
                    var competence = this.dataValues;
                    Competence.build(competence)
                        .save().ok(onSuccess).error(onError);
                },
                updateById: function (quote_id, onSuccess, onError) {
                    var id = quote_id;
                    var quotes = this.quotes;

                    Location.update({quotes: quotes}, {where: {id: id}})
                        .success(onSuccess).error(onError);
                },
                removeById: function (quote_id, onSuccess, onError) {
                    Location.destroy({where: {id: quote_id}}).success(onSuccess).error(onError);
                }
            }
        }
    ),
    competence_type = sequelize.define('competence_type', {
        id: DataTypes.INTEGER,
        name: DataTypes.STRING
    });
Competence.belongsTo(competence_type,{foreignKey: 'competence_type_id'});

注意add函数,它是我用来添加新元素的函数。

这是我的competence变量:

enter image description here

但是,一旦我保存,我的回调函数不会被调用onSuccess也不会onError

任何人都可以帮助我,我会疯了!!

1 个答案:

答案 0 :(得分:1)

Sequelize使用bluebird作为承诺。因此,您应该使用.then.catch方法,而不是.success.ok)和.error.error在蓝鸟中有另一种含义(见here)。因此,例如.add方法可以写成:

add: function (onSuccess, onError) {
    var competence = this.dataValues;

    Competence.build(competence).save().then(onSuccess).catch(onError);
}
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