Question

我有以下

HTML

<input type="checkbox" name="symbols[]" value="1" />
<input type="checkbox" name="symbols[]" value="2" />
<input type="checkbox" name="symbols[]" value="3" />
etc...
<select name="city">
   <option value="Dublin">Dublin</option>
   <option value="Cork">Cork</option>
   etc ...
</select>

Laravel

return DB::table('restaurants')
            ->select('restaurants.id as restaurantId',
                    'restaurants.image_id as imageId',
                    'restaurants.name as restaurantName',
                    'restaurants.slug as restaurantSlug',
                    'restaurants.description as restaurantDescription')
            ->leftJoin('restaurants_symbols', 'restaurants_symbols.restaurant_id', '=', 'restaurants.id')
            ->leftJoin('restaurants_locations', 'restaurants_locations.restaurant_id', '=', 'restaurants.id')
            ->groupBy('restaurants_symbols.restaurant_id')
            ->where(function($q) use ($input) {
                $q->whereIn('restaurants_symbols.symbol_id', $input['symbol']);

                if(!empty($input['city'])) {
                    $q->where('restaurants_locations.city', $input['city']);
                }
            })
            ->get();

如果用户选中了value1和value2，那么查询将返回包含value1或value2的所有餐馆，所以我想实现的只是返回只有代表value1 AND value2的符号的餐馆。 / p>

有什么建议吗？我想也许可以按原样返回值，然后在foreach循环中过滤它们但是我不知道它是否可能，如果它是我没有看到如何做到这一点的逻辑，对此的任何想法？

Answer 1

试试这个..

用于for condition的where循环。它为你的case返回value1和value2

$symbol=$input['symbol'];
    return DB::table('restaurants')
                ->select('restaurants.id as restaurantId',
                        'restaurants.image_id as imageId',
                        'restaurants.name as restaurantName',
                        'restaurants.slug as restaurantSlug',
                        'restaurants.description as restaurantDescription')
                ->leftJoin('restaurants_symbols', 'restaurants_symbols.restaurant_id', '=', 'restaurants.id')
                ->leftJoin('restaurants_locations', 'restaurants_locations.restaurant_id', '=', 'restaurants.id')
                ->groupBy('restaurants_symbols.restaurant_id')
                ->where(function($q) use ($input) {
    for($i=0;$i<count($symbol);$i++)                //add forloop
    {
                    $q->where('restaurants_symbols.symbol_id', $symbol[$i]);
    }

                    if(!empty($input['city'])) {
                        $q->where('restaurants_locations.city', $input['city']);
                    }
                })
                ->get();

Laravel根据用户选择返回结果

1 个答案: