在Django上更新数据库中的模型对象

时间:2015-03-06 07:56:09

标签: django django-models django-views

我是Django的新手,为了学习目的,我正在尝试使用linkedn API构建我自己的网站来显示我的个人资料。以下是我的代码示例。看到整个地段:

https://github.com/javiee/django-site

models.py

class Profile(models.Model):

user = models.ForeignKey(User)
first_name = models.CharField(max_length=20)
last_name = models.CharField(max_length=20)

def __str__(self):
    return self.first_name, self.last_name

class Education(models.Model):

user = models.ForeignKey(User)
school_name =  models.CharField(max_length=100) 
field_study =  models.CharField(max_length=100)
degree =  models.CharField(max_length=100)
start_date =  models.CharField(max_length=20)
end_date =  models.CharField(max_length=20)

和views.py

  profile = Profile(first_name = content['firstName'], 
  last_name = content['lastName'],
  user = request.user)
  profile.save()

#Education model
content_educ = content['educations']['values']
for value in content_educ:
    education = Education(school_name = value['schoolName'],
            user = request.user,
            field_study = value['fieldOfStudy'],
            degree = value['degree'],
            start_date = value['startDate']['year'] ,
            end_date = value['endDate']['year'])
    education.save()

这一切都有效但我的问题是每次检查链接时,代码会再次保存所有对象。理想情况下,在调用.save()方法时,根据配置文件“更新”字段。我已阅读下一个链接https://docs.djangoproject.com/en/1.7/ref/models/instances/#saving-objects

但是我没有设法使它工作,也许foreigns键没有正确设置所以任何建议/帮助/提示将非常感激。谢谢!

2 个答案:

答案 0 :(得分:1)

使用update_or_create()方法:

Education.objects.update_or_create(
                   school_name=value['schoolName'],
                   user = request.user,
                   defaults={'field_study': value['fieldOfStudy'],
                             'degree': value['degree'],
                             'start_date': value['startDate']['year'] ,
                             'end_date': value['endDate']['year']})

答案 1 :(得分:1)

您遇到的问题是您要在以下行中实例化新的Education实例:

    education = Education(school_name = value['schoolName'],
        user = request.user,
        field_study = value['fieldOfStudy'],
        degree = value['degree'],
        start_date = value['startDate']['year'] ,
        end_date = value['endDate']['year'])

当Django试图保存这些新实例(尚未定义id的实例)时,Django继续并插入记录而不是进行所需的更新。

要进行更新,您可以尝试获取记录,捕获DoesNotExist例外:

try:
    education = Education.objects.get(school_name=value['schoolName'],
        user=request.user,
        field_study=value['fieldOfStudy'],
        degree=value['degree'],
        start_date=value['startDate']['year'],
        end_date=value['endDate']['year'])
except Education.DoesNotExist:
    education = Education(school_name=value['schoolName'],
        user=request.user,
        field_study=value['fieldOfStudy'],
        degree=value['degree'],
        start_date=value['startDate']['year'],
        end_date=value['endDate']['year'])

然后应用您想要/需要的任何更新。

或者您可以使用get_or_create执行相同操作:

(education, created) = Education.objects.get_or_create(school_name=value['schoolName'],
        user=request.user,
        field_study=value['fieldOfStudy'],
        degree=value['degree'],
        start_date=value['startDate']['year'],
        end_date=value['endDate']['year'])

如果您不想按所有这些值查找实例(它们是AND编辑),但想要使用特定值初始化新实例,则应该查找defaults关键字get_or_create

或者您可以按照catavaran的建议使用update_or_create

编辑:或者,如果您只想直接更新记录而不获取它(这也适用于多个对象),您可以使用queryset.update

Education.objects.filter(attribute=value, ...).update(attribute2=value2, ...)
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