Question

目前，我的代码工作正常，但问题是我遇到了UIPickerView的问题。现在，如果我选择Cameron品牌，那么它将归属于Cameron品牌，但如果我选择Shaffer品牌，它仍然适用于var Cameron。

如何重写代码，以便在选择其他品牌时，选择不同的数组？

例如，如果我选择品牌卡梅隆，它选择卡梅隆，如果我选择品牌谢弗，它选择谢弗等。

class Picker: UIViewController, UIPickerViewDelegate, UITextFieldDelegate

{
    var activeTextField:UITextField?

    @IBOutlet var pickerView1: UIPickerView!
    @IBOutlet var pickerView2: UIPickerView!
    @IBOutlet var pickerView3: UIPickerView!

    @IBOutlet var textField1: UITextField!
    @IBOutlet var textField2: UITextField!
    @IBOutlet var textField3: UITextField!

    var brand = ["Cameron","Shaffer", "Hydril"]
    var cameron = ["D Annular Preventer", "UM Ram Preventer", "U Ram Preventer"]
    var shaffer = ["Spherical Annular Preventer", "LXT Ram Preventer", "NXT Ram Preventer"]
    var size = ["7 1/16","11","13 5/8"]
    var size2 = ["8 5/8","12","15 5/8"]

    override func viewDidLoad() {

        super.viewDidLoad()

        pickerView1 = UIPickerView()
        pickerView2 = UIPickerView()
        pickerView3 = UIPickerView()

        pickerView1.tag = 0
        pickerView2.tag = 1
        pickerView3.tag = 2 

    }

    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int  {
        return 1
    }

    func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {

        if pickerView.tag == 0 {
            return brand.count
        } else if pickerView.tag == 1 {
            return cameron.count
        } else if pickerView.tag == 2 {
            return size.count
        }
        return 1
    }

    func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! {

        if pickerView.tag == 0 {
            return brand[row]
        } else if pickerView.tag == 1 {
            return cameron[row]
        } else if pickerView.tag == 2 {
            return size[row]
        }
        return ""
    }

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int)  {

        if pickerView.tag == 0 {
            textField1.text = brand[row]
        } else if pickerView.tag == 1 {
            textField2.text = cameron[row]
        } else if pickerView.tag == 2 {
            textField3.text = size[row]
        } 
    }

Answer 1

cameron必须替换为动态查找。您需要一个品牌词典，然后您可以将其与UI联系起来：

[当我写这篇文章时，我发现变量名称很糟糕;请避免0,1,2，编号变量的精神错误，3,4，bleah]

在班级：

var brandLookup = [ "cameron": [ "x", "y", "z"], "anotherBrand": ... ]

然后你的代表职能：

func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
    if pickerView.tag == 0 {
        return brand.count
    } else if pickerView.tag == 1 {
        let brand = textField1.text
        let modelsForBrand = brandLookup[brand]!
        return modelsForBrand.count
    }
    ...
}

类似地：

func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int)  {
   if pickerView.tag == 0 {
        textField1.text = brand[row]
        pickerView2.reloadAllComponents() // this picker has new data now
   } else if pickerView.tag == 1 {
       let brand = textField1.text
       let modelsForBrand = brandLookup[brand]!
       textField2.text = modelsForBrand[row]
   }
...
}

最后：

func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! {
    // left as an exercise for you
}

UIPickerView选择数组Swift

1 个答案: