Question

上一页（添加为编辑）

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        <?php

        $scripte = ($_POST["scriptake"]);
         $scriptot =($_POST["scriptot"]);
         include 'config.php';

     echo '<h2>'.$scripte.' Equipment</h2>';
     echo '<h2>Total Hours '.$scriptot.'</h2>';

echo'<table class="table table-responsive"><tr><form action="equiptest.php" method="post"><th>Script Hour</th><th>Equipment Required</th><th>Stage</th></tr>';
$x = 1;
$p = 1;
$r=1;
while($x <= $scriptot ) {
  echo "<tr><td>".$x++."</td><td><input name='equip".$r++."'` ></td><td><input name='stage".$p++."'><input name='ohyeah' type='hidden' value= '".$scriptot."'></td></tr>";
}


 echo'<tr><td colspan="2"><input type="submit" class="btn btn-primary"></td></tr></form></table>';


        ?>







       </div>

我可以使用post变量执行此操作。我得到了不确定。但是，如果我写

 equip1 = ($_POST["equip1"]);
 echo $equip1;

它有效

<?php



$scriptot = ($_POST["ohyeah"]);// working
$y = 1;
$x = 1;
$r= 1;

while($x <= $scriptot ) {//working

 ${"equip".$x} = ($_POST["equip".$x]); //not working
 echo ${"equip" .$x};//not working
 $x++; // working
 }

我正在尝试创建动态变量。在这种情况下的想法是将POST插入数据库所以想要 $ equip1 $ equip2 $ equip3等感谢

Answer 1

出于组织目的，您应该使用数组。

例如，在表单中，您可以将输入名称设置为“equip [1]”，该值将导入到PHP $_POST['equip'][1]。然后你可以运行：

foreach($_POST['equip'] as $key=>$value) {
   # where $key = 1, the $value will be of equip[1]
}

可能不完全是你所追求的，但它似乎比你正在尝试的解决方案更清晰。

Answer 2

我就是这样尝试的。

<?php while ( have_posts() ) : the_post(); ?>
           
     <div class="contentTitle"><?php the_title(); ?></div>
     <div class="contentText">
        <?php the_content(); ?>
    </div>
            
<?php endwhile ?>

php while循环动态post变量

2 个答案: