Question

我想使用php将google plus登录到我的网站。为此我用过 -

<?php

class G_login {

    function lib_include() {
       require_once 'lib/src/Google_Client.php';
       require 'lib/src/contrib/Google_Oauth2Service.php';
       require_once 'lib/src/contrib/Google_PlusService.php';
       }

       function login(){
        session_start();       
        $this->lib_include();
        $api = new Google_Client();
        $api->setApplicationName("InfoTuts");
        $api->setClientId('XXXXX-2gsbbr0eii1ul6kfkmvqmjao80mlp67b.apps.googleusercontent.com');   // Enter Client ID
        $api->setClientSecret('Khi69F8wZZj8XbrujINvTsKg');    // Enter Client Secret
        $api->setAccessType('online');
        $api->setScopes(array('https://www.googleapis.com/auth/plus.login', 'https://www.googleapis.com/auth/plus.me', 'https://www.googleapis.com/auth/userinfo.email', 'https://www.googleapis.com/auth/userinfo.profile'));
        $api->setRedirectUri('http://localhost/socialposting/profile/google/GooglePlus/login.php');   // Enter redirect URI
        $service = new Google_PlusService($api);
        $oauth2 = new Google_Oauth2Service($api);
        $api->authenticate();
        $_SESSION['token'] = $api->getAccessToken();        
         if (isset($_SESSION['token'])) {
            $set_asess_token = $api->setAccessToken($_SESSION['token']);
            }        
        if ($api->getAccessToken()) {
            $data = $service->people->get('me');
            $user_data = $oauth2->userinfo->get(); 
              //echo "<pre>";print_r($user_data);echo "</pre>";
            ?>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Login with Google Plus Oauth - InfoTuts</title>
 <link rel="stylesheet" type="text/css" media="all" href="style.css">
</head>
<div id="userinfo">
<table class="usertable">
<tr>
    <td>Your Name: </td>
    <td><?php print $user_data['name']; ?></td>
    <td rowspan="5" valign="top"><img src="<?php print $user_data['picture']; ?>?sz=80" /></td>
</tr>
<tr>
    <td> Your Email</td>
    <td><span style="background:#FFFF00;"><?php print $user_data['email']; ?></span></td>
</tr>
<tr>
    <td>Your Profile Link</td>
    <td><?php print $user_data['link']; ?></td>
</tr>

</table>
</div>

</body>
</html>
<?php

       }

       } 
}

$obj= New G_login();
$obj->login();


?>

它返回用户ID，个人资料，图片，电子邮件等，但如果再次刷新它显示的页面：

=致命错误：在D：\ xamp \ htdocs \ socialposting \ profile \ google \ GooglePlus \ lib \ src \ auth \ Google_OAuth2中显示错误“Google_AuthException”，并显示错误“获取OAuth2访问令牌时出错，消息：'invalid_grant'' .php：115堆栈跟踪：＃0 D：\ xamp \ htdocs \ socialposting \ profile \ google \ GooglePlus \ lib \ src \ Google_Client.php（127）：Google_OAuth2-＆gt; authenticate（Array，NULL）＃1 D：\ xamp \ htdocs \ socialposting \ profile \ google \ GooglePlus \ login.php（23）：Google_Client-＆gt; authenticate（）＃2 D：\ xamp \ htdocs \ socialposting \ profile \ google \ GooglePlus \ login.php（69）：第115行的D：\ xamp \ htdocs \ socialposting \ profile \ google \ GooglePlus \ lib \ src \ auth \ Google_OAuth2.php中的G_login-＆gt; login（）＃3 {main}

我该如何解决这个错误。我还想发布谷歌+个人资料和页面。感谢

如何使用PHP将google plus登录集成到我的网站

0 个答案: