Question

我想创建程序从用户读取超过10个数字，并找到最大数量和最小数量，然后打印用户的所有数字。

这是我的计划，但我不知道如何找到最大数量和最小数量：

import java.io.*;

public class ass3 {
    public static void main (String [] args) throws IOException
    {
        int times , num1 ;
        int max , min;
        System.out.print("How many numbers you want to enter?\n*moer than five number");
        times=IOClass.getInt();
        if (times>5) {
           for(int i = 0;i<times;i++){
              System.out.println("please type the "+i+ "number");
              num1=IOClass.getInt();
           }
        }           
    }
}

Answer 1

如果您像这样初始化min和max：

int min = Integer.MAX_VALUE;
int max = Integer.MIN_VALUE;

您可以检查新号码是否小于min或大于max，并在需要时进行更改：

int num = ...;
if (num < min) {
    min = num;
}
if (num > max) {
    max = num;
}

Answer 2

这是我的解决方案，希望有所帮助：

import java.util.Scanner;

public class Test 
{

    public static void main(String[] args) 
    {       
        Scanner in = new Scanner(System.in);
        System.out.print("How many numbers you want to enter?\nThe number must be grater than 5");
        int times = in.nextInt();
        if (times > 5)
        {
            int[] numbers = new int[times];
            int min = Integer.MAX_VALUE; 
            int max = Integer.MIN_VALUE;
            for(int i = 0; i < times; i++)
            {
                System.out.println("Please type the " + i + " number:");
                int number = in.nextInt();
                numbers[i] = number;
                if(number < min)
                {
                    min = number;
                }
                if(number > max)
                {
                    max = number;
                }
            }
            System.out.println("Max: " + max);
            System.out.println("Min: " + min);
        }
        in.close();
    }
}

我无法找到最大值和最小值

2 个答案: