Question

我想制作每周一次的表格，我需要在html标记中附加日期。到目前为止，我得到了这段代码：

    <table class="schedule-table">
        <tr class="days-tr">
         <td> 
            <span><?php echo $date = date("dS",strtotime('monday this week')).' -  '.date("dS",strtotime("sunday this week")); ?> </span>
            <span> <?php echo $date = date("M-Y",strtotime('monday this week')); ?></span>
        </td>
        <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('monday this week')); ?>">Monday</td>
        <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('tuesday this week')); ?>">Tuesday</td>
        <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('wednesday this week')); ?>">Wednesday</td>
        <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('thursday this week')); ?>">Thursday</td>
        <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('friday this week')); ?>">Friday</td>
        <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('saturday this week')); ?>">Saturday</td>
        <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('sunday this week')); ?>">Sunday</td>
        </tr>
    </table>

这是输出：

<table class="schedule-table">
    <tbody>
        <tr class="days-tr">
            <td> 
                <span>16th -  15th </span>
                <span> Mar-2015</span>
            </td>
            <td data-workout-day="16-Mar-2015">Monday</td>
            <td data-workout-day="10-Mar-2015">Tuesday</td>
            <td data-workout-day="11-Mar-2015">Wednesday</td>
            <td data-workout-day="12-Mar-2015">Thursday</td>
            <td data-workout-day="13-Mar-2015">Friday</td>
            <td data-workout-day="14-Mar-2015">Saturday</td>
            <td data-workout-day="15-Mar-2015">Sunday</td>
        </tr>
    </tbody>
</table>

正如您所看到的那样需要从下周开始，而不是2015年3月9日？如何解决这个问题才能正确显示？（例如，如果我们有星期五13日至3月，我希望星期一，星期二，星期日的日期不是以下。

Answer 1

strtotime非常强大，可以接受很多字符串来获得所需的日期。在这种情况下，您希望this week获取此周的日期。

通过更改＆＃39;下周一＆＃39;等星期一星期一＆＃39;你得到当周的星期一的日期：

<table class="schedule-table">
    <tr class="days-tr">
    <td> 
        <span><?php echo $date = date("dS",strtotime('this week')).' -  '.date("dS",strtotime("this week sunday")); ?> </span>
        <span> <?php echo $date = date("M-Y",strtotime('monday this week')); ?></span>
    </td>
    <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('this week monday')); ?>">Monday</td>
    <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('this week tuesday')); ?>">Tuesday</td>
    <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('this week wednesday')); ?>">Wednesday</td>
    <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('this week thursday')); ?>">Thursday</td>
    <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('this week friday')); ?>">Friday</td>
    <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('this week saturday')); ?>">Saturday</td>
    <td data-workout-day="<?php echo $date = date("d-M-Y",strtotime('this week sunday')); ?>">Sunday</td>
    </tr>
</table>

生成：

<table class="schedule-table">
    <tbody>
        <tr class="days-tr">
            <td> 
                <span>09th -  15th </span>
                <span> Mar-2015</span>
            </td>
            <td data-workout-day="09-Mar-2015">Monday</td>
            <td data-workout-day="10-Mar-2015">Tuesday</td>
            <td data-workout-day="11-Mar-2015">Wednesday</td>
            <td data-workout-day="12-Mar-2015">Thursday</td>
            <td data-workout-day="13-Mar-2015">Friday</td>
            <td data-workout-day="14-Mar-2015">Saturday</td>
            <td data-workout-day="15-Mar-2015">Sunday</td>
        </tr>
    </tbody>
</table>

Answer 2

如果你假设你的星期从星期一开始

然后首先检查

$day = date('l')
if($day != 'Monday'){
echo $date = date("d-M-Y",strtotime( "previous monday" ));
}

显示从星期一到星期日的日期

2 个答案: