具有相似列名的动态轴

时间:2015-03-10 14:14:13

标签: sql sql-server sql-server-2008-r2 pivot

我正在寻找一种方法,将不同数量的行转移到sql server 2008 R2中的列。我在查询中创建了数据列RANK,因为最终我希望将透视列名称标记为RANK列中的值。然后,如果以某种方式我可以STUFF将其他3个字段值合并为一个字段,我将能够迭代后端lang中的行并适当地分割字段结果。

以下是当前数据集:

data table 1 (original data set)

我希望枢轴的最终结果产生如下结果:

data table 2 (end result)

我还没有找到任何能够在这个"动态"办法。任何帮助将不胜感激。

1 个答案:

答案 0 :(得分:4)

如上所述,您需要区分每个Rank值。您已经说过这是一个计算值,您可以在每个值的末尾添加一个数字。一旦你添加了这个号码,你仍然需要转动它。

首先看到这个的最简单方法是首先编写查询的硬编码版本。

示例数据:

create table yourdata
(
    id int,
    code varchar(50),
    created datetime,
    [rank] varchar(50)
);

insert into yourdata
select 285856, 'J7609', '2015-01-19', 'Principle' union all
select 285856, 'J7613', '2015-01-19', 'Other' union all
select 285856, 'J0456', '2015-01-19', 'Other' union all
select 285856, 'J0694', '2015-01-19', 'Other' union all
select 285856, 'J1885', '2015-01-19', 'Other' union all
select 285856, 'J2060', '2015-01-19', 'Other' union all
select 285856, 'J2930', '2015-01-19', 'Other';

静态查询:

select Principle_1, Other_1, 
    Other_2, Other_3, Other_4,
    Other_5, Other_6
from
(
    -- using row_number to get unique id for each rank
    select 
        data = cast(id as varchar(10)) +' | '+ code +' | '+ convert(varchar(10), created, 112),     
        [rank] = [rank] + '_' +cast(row_number() over(partition by id, [rank] 
                                                        order by id) as varchar(10))
    from yourdata
) d
pivot
(
    max(data)
    for [rank] in (Principle_1, Other_1, Other_2, Other_3, Other_4,
                    Other_5, Other_6)
) p;

现在要动态,你将创建一个带有列名的sql字符串,然后执行该字符串:

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT  ',' + QUOTENAME([rank] + '_' +cast(rn as varchar(10))) 
                    from
                    (
                        select [rank],
                            rn = row_number() over(partition by id, [rank] 
                                                    order by id) 
                        from  yourdata
                    ) d
                    group by [rank], rn
                    order by rn, [rank] desc
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT ' + @cols + '
            from 
             (
                select 
                    data = cast(id as varchar(10)) +'' | ''+ code +'' | ''+ convert(varchar(10), created, 112),     
                    [rank] = [rank] + ''_'' +cast(row_number() over(partition by id, [rank] 
                                                                    order by id) as varchar(10))
                from yourdata
            ) x
            pivot 
            (
                max(data)
                for [rank] in (' + @cols + ')
            ) p '

exec sp_executesql @query;

这会得到一个结果:

+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+
|        Principle_1        |          Other_1          |          Other_2          |          Other_3          |          Other_4          |          Other_5          |          Other_6          |
+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+
| 285856 | J7609 | 20150119 | 285856 | J7613 | 20150119 | 285856 | J0456 | 20150119 | 285856 | J0694 | 20150119 | 285856 | J1885 | 20150119 | 285856 | J2060 | 20150119 | 285856 | J2930 | 20150119 |
+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+---------------------------+