浏览器Url的正则表达式

时间:2010-05-24 18:56:55

标签: javascript regex url

我是JavaScript的新手

我需要一个正则表达式

允许这两种形式

例如:

  1. http://www.google.com
  2. www.google.com

4 个答案:

答案 0 :(得分:1)

var url_pattern = new RegExp("((ftp|http|https)(:\/\/))?([a-zA-Z0-9]+[.]{1}){2}[a-zA-z0-9]+(\/{1}[a-zA-Z0-9]+)*\/?", "i");

return url_pattern.test(url);

答案 1 :(得分:0)

(ftp|http|https):\/\/(\w+:{0,1}\w*@)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%@!\-\/]))?

这很有效。

答案 2 :(得分:0)

我刚刚撰写了一篇关于识别大多数使用格式的网址的博文,例如:

www.google.com http://www.google.com mailto:somebody@google.com somebody@google.com www.url-with-querystring.com/?url=has-querystring

使用的正则表达式是/((([A-Za-z]{3,9}:(?:\/\/)?)(?:[-;:&=\+\$,\w]+@)?[A-Za-z0-9.-]+|(?:www.|[-;:&=\+\$,\w]+@)[A-Za-z0-9.-]+)((?:\/[\+~%\/.\w-_]*)?\??(?:[-\+=&;%@.\w_]*)#?(?:[\w]*))?)/但是我建议您到http://blog.mattheworiordan.com/post/13174566389/url-regular-expression-for-links-with-or-without-the查看完整的工作示例以及正则表达式的解释,以防需要扩展或调整它。< / p>

答案 3 :(得分:0)

^((?:(?:https?|ftp):)?\/\/?)?(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)(?:\.(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)*(?:\.(?:[a-z\x{00a1}-\x{ffff}]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?$

测试一下! https://regex101.com/r/qQ8uV6/1

摘自寻找完美的网址验证正则表达式 https://mathiasbynens.be/demo/url-regex(稍加修改)。

@diegoperini

如果您在JavaScript中测试它,那么您将获得一个不错的

  

ParseError:解析正则表达式时出错:正则表达式无效

     

...

     

字符类

中的范围乱序

您需要将\x{xxxx}替换为\uxxxx。所以在 JavaScript 中,它将是:

^(?:(?:https?|ftp):\/\/)?(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\ufff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?$

就像JavaScript Unicode Regex - Range out of order in character class

中所述
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