Question

我希望在文件上传后返回上一页并成功上传＆＃34;文件＆＃34;在上传页面上。

在顶部的upload.php中，我放置了

sesssion_start();

在文件上传脚本的末尾，我已经放置了

$_SESSION['upload_success'] = TRUE;
header("Location: stream.php");

现在我知道我需要在html文档中加入一些代码，但不确定需要进行什么。下面是我的html表单脚本

<form action="upload.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="MAX_FILE_SIZE" value="90000000" />
 Select video to upload:
Please choose a file: <input name="uploadedfile" type="file" /><br /> 
<input type="submit" value="Upload File" />

我知道它会与此类似，但不确定我将如何放置它。

 session_start();
 if (isset($_SESSION['upload_success']) && $_SESSION['upload_success']) {
 echo "File uploaded successfully";
 }

如果有人可以引导我将HTML代码添加到正确的位置，我会非常感激

评论后我修改我的PHP代码看起来像这样。

<?php error_reporting(E_ALL); ini_set('display_errors', 1);
sesssion_start();
$target_path = "upload/";
$target = $target_path . basename($_FILES['uploadedfile']['name'] );
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'] , $target))
{ 
echo "The file ". basename( $_FILES['uploadedfile']['name'] ). " has been      uploaded"; 
  } 
 else {
   echo "Sorry, there was a problem uploading your file."; 
    }
   $_SESSION['upload_success'] = TRUE;
   header("Location: stream.php");
   exit();

stream.php中的语法为：

    <?phpsession_start();
    if (isset($_SESSION['upload_success']) && $_SESSION['upload_success']) {
    echo "File uploaded successfully";
    }
    ?>

谢谢，

马克

Answer 1

Nota：你也不能同时使用echo和header，因为这会被认为是在header之前输出，所以我们只使用一个会话数组作为消息，并将标题重定向到“upload_form.php”，然后显示相应的之后该页面上的消息。

使用session_destroy()也可以销毁以前的所有会话。

旁注：使用两个单独的文件。

HTML表单：调用此“upload_form.php”

<?php 
session_start();
session_destroy();
?>

<form action="stream.php" method="post" enctype="multipart/form-data">

<input type="hidden" name="MAX_FILE_SIZE" value="90000000" />
Select video to upload:
Please choose a file: <input name="uploadedfile" type="file" /><br />

 <input type="submit" value="Upload File">
 </form>

<?php 
if(isset($_SESSION['upload_success'])){
    echo $_SESSION['upload_success'];
}

else{
    echo "Please select a file.";
}

?>

PHP（文件2）：调用此“stream.php”

<?php 
session_start();

$target_path = "upload/";
$target = $target_path . basename($_FILES['uploadedfile']['name'] );

if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'] , $target))
{
$_SESSION['upload_success'] = "File successfully uploaded.";
header("Location: upload_form.php");
exit;
  } 

 else {
$_SESSION['upload_success'] = "Sorry, there was a problem uploading your file.";

header("Location: upload_form.php");
exit;
    }

修改

在if(move_uploaded_file...
之后修改并添加以下内容
if(isset($_FILES['uploadedfile']) && !empty($_FILES['uploadedfile'])){ $target_path = "upload/"; $target = $target_path . basename($_FILES['uploadedfile']['name']); }

Answer 2

您的代码运行正常，但在执行回显成功消息后，应删除具有未设置功能的会话['upload_success']。试试

 unset( $_SESSION['upload_success'])

在

之后的stream.php中

 echo "File uploaded successfully";

更新：如果你想在一个页面上完成所有这些工作，你可以像下面这样做：

 if(isset($_SESSION['upload_success']) and $_SESSION['upload_session'])
   {
//echo success message
//remove session
}
if(isset($_POST['file'])){
//upload process , if it was successfull make seesion true...

}
else {

//show form

}

Answer 3

配售

$_SESSION['upload_success'] = TRUE;
header("Location: stream.php");

最后，我相信，无论文件上传的实际情况如何，都会设置为true，没有检查条件。

除非脚本在失败时有退出命令，否则它最终会到达以下部分：“将上传成功设置为true，然后转到stream.php”，而不是说“如果上传成功” ，将上传成功设置为true，然后转到stream.php“

我会尝试：

    <?php 
error_reporting(E_ALL); ini_set('display_errors', 1);

session_start();

if($_FILES['uploadedfile']['size'] == 0)//In other words, if no file was selected.
    {
    $_SESSION['upload_success'] = 4;//File wasn't selected
    header("Location: stream.php");
    exit();
    }   

if(!file_exists('upload/' . basename($_FILES['uploadedfile']['name'])))
    {       
    $_SESSION['upload_success'] = (move_uploaded_file($_FILES['uploadedfile']['tmp_name'],'upload/' . basename($_FILES['uploadedfile']['name'])) ? 1 : 2);
    }
elseif(file_exists('upload/' . basename($_FILES['uploadedfile']['name'])))
    {
    $_SESSION['upload_success'] = 3;
    }

header("Location: stream.php");
exit(); 
?>

现在在stream.php中你有if语句显示消息，而不是这样做：

<?php
session_start();

switch (@$_SESSION['upload_success']) {
    case 1:
        echo "File uploaded successfully";
        break;
    case 2:
        echo "Sorry, there was a problem uploading your file.";
        break;
    case 3:
        echo "A file with that name already exists!";
        break;
    case 4:
        echo "You must select a file to upload!";
        break;
}
unset($_SESSION['upload_success']);
 ?>//So if you reload stream.php yet another time no messages will be displayed again for no reason. ie. none of the cases will match an unset variable.

最后，在header(Location: "somepage.php");

之前，您无法回显（或做任何类型的输出，供用户查看）

在用户可以读取输出之前，页面将会切换。

您的代码目前在您的问题中编写的方式可能会发生以下情况：

服务器回声“抱歉，上传文件时出现问题”，用户永远不会看到。
$ _ SESSION ['upload_success']然后设置为TRUE，这显然与＃1不一致。
然后将用户发送到stream.php，其中有成功消息显示。

另一种更有用的场景描述方法也可以解决您的问题（在upload.php中）：

else 
    {
    die("Sorry, there was a problem uploading your file."); 
    }

希望有所帮助！

Answer 4

要获得快速解决方案，您可以使用Ravi Kusuma的jQuery File Upload Plugin或AJAX解决方案来执行此操作。

但是，上面提出的另一个选择是以编程方式构造/输出带有一些javascript的HTML表单，并让它将消息发送到stream.php：

CAVEAT：我自己没试过，但我想不出为什么不行。有人请确认我的理智吗？ - 自己测试：它有效。

<?php
    //upload.php

    //Do file upload stuff, then:

    $out = '
        <form id="frmUpOkay" action="stream.php" method="post">
            <input name="upMsg" value="Upload Successful" />
        </form>
        <script type="text/javascript">
            $(function(){
                $("#frmUpOkay").submit();
            });
        </script>
    ';
    echo $out;
?>

您还必须将此位添加到stream.php文件的顶部：

<?php
    if ( isset($_POST['upMsg']) && isset($_POST['upMsg']) != '' ){
        $upMsg = $_POST['upMsg']; //you should sanitize this input
    }else{
        $upMsg = '';
    }
?>
<html>
<head>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
</head>
<body>
    <div>
        Your normal website content is here.<br>
        <br>
        Upload message: <?php echo $upMsg; ?> <br>
        <br>
    </div>
</body>

注意：

以上代码使用jQuery，因此您需要在upload.php页中包含jQuery库（如上所示）。

文件上传返回上传html页面

4 个答案: