Question

我想找到不同的FKID，其中IsProcessed对于相同的FKID是真的。 e.g。

CID    FKID    DataField    IsProcessed

1      1       Test         1
2      1       Test         1
3      2       Test         0
4      2       Test         1
5      3       Test         0
6      3       Test         0
7      4       Test         1
8      5       Test         0
9      6       Test         1
10     6       Test         1
11     6       Test         1

我想获得以下FKID返回1,4,6 因为这些是所有实例的isprocessed为真的FKID。

任何帮助将不胜感激！谢谢！

Answer 1

您可以使用SUM() OVER和COUNT() OVER

;WITH CTE AS(
    SELECT
        *,
        IsProcessedCount = SUM(CASE WHEN IsProcessed = 1 THEN 1 ELSE 0 END) OVER(PARTITION BY FKID),
        cc = COUNT(*) OVER(PARTITION BY FKID)
    FROM TEST
)
SELECT
    DISTINCT FKID
FROM CTE
WHERE IsProcessedCount = cc

使用GROUP BY和HAVING：

SELECT FKID
FROM Test
GROUP BY FKID
HAVING COUNT(FKID) = COUNT(CASE WHEN IsProcessed = 1 THEN 1 ELSE NULL END)

另一种方式：

SELECT FKID
FROM Test
GROUP BY FKID
HAVING COUNT(FKID) = SUM(CAST(IsProcessed AS INT))

只需将TEST替换为您的表格。

Answer 2

SELECT FKID
FROM TableName
GROUP BY FKID
HAVING (MIN(IsProcessed) = 1)

或者

SELECT FKID
FROM TableName
GROUP BY FKID
HAVING (MIN(CAST(IsProcessed AS INT)) = 1)

如果IsProcessed不是数字类型：

Answer 3

另一种方法，使用相关的not exists谓词：

select fkid from TableName t
where IsProcessed = 1
  and not exists 
    (select 1 from TableName where IsProcessed = 0 and FKID = t.FKID)
group by fkid

或使用not in：

select fkid from TableName t
where IsProcessed = 1
  and fkid not in 
    (select fkid from TableName where IsProcessed = 0 and FKID = t.FKID)
group by fkid

选择不同的行，其中列中的所有值都是相同的SQL Server

3 个答案: