根据条件结果增加foreach循环中的计数器

Question

我有一个从mysql查询生成的数组，如下所示。它们的关键是order_id值。

订购数组

Array
(
    [2646] => Array
        (
            [order_id] => 2646
        )

    [2647] => Array
        (
            [order_id] => 2647
        )

    [2650] => Array
        (
            [order_id] => 2650
        )

    [2658] => Array
        (
            [order_id] => 2658
        )

)

我正在寻找使用来自另一个数组的项目向数组的每一行添加项目。

order_items数组

Array
(
    [0] => Array
        (
            [order_id] => 2646
            [prod_code] => 2811
            [order_qty] => 1
        )

    [1] => Array
        (
            [order_id] => 2646
            [prod_code] => 2812A
            [order_qty] => 3
        )

    [2] => Array
        (
            [order_id] => 2647
            [prod_code] => 2812A
            [order_qty] => 2
        )

    [3] => Array
        (
            [order_id] => 2647
            [prod_code] => 2810
            [order_qty] => 2
        )

    [4] => Array
        (
            [order_id] => 2650
            [prod_code] => 2906
            [order_qty] => 1
        )

    [5] => Array
        (
            [order_id] => 2650
            [prod_code] => 2908
            [order_qty] => 6
        )

    [6] => Array
        (
            [order_id] => 2650
            [prod_code] => 2909
            [order_qty] => 3
        )

    [7] => Array
        (
            [order_id] => 2650
            [prod_code] => 2913
            [order_qty] => 1
        )

    [8] => Array
        (
            [order_id] => 2658
            [prod_code] => 2880
            [order_qty] => 3
        )

    [9] => Array
        (
            [order_id] => 2658
            [prod_code] => 2881
            [order_qty] => 3
        )

    [10] => Array
        (
            [order_id] => 2658
            [prod_code] => 2882
            [order_qty] => 1
        )

)

我在解决问题时如何绕过order_items数组并将prod_code和order_qty值插入order数组{{1}值匹配。这是我到目前为止所做的。

order_id

我的问题是，当我们查看新的// create orders array - key by order_id while ($order = mysqli_fetch_assoc($order_rows)) { $orders[$order['order_id']] = $order; } // create the order_items array while ($item = mysqli_fetch_assoc($item_rows)) { $order_items[] = $item; } // update orders array with ordered items $item_index = 1; foreach ($order_items as $key => $value) { // get the order id $item_order_id = $value['order_id']; // update orders array with ordered items grouped by order_id if ($item_order_id == $orders[$item_order_id]['order_id']) { $orders[$item_order_id]['prod_code_'.$item_index] = $value['prod_code']; $orders[$item_order_id]['order_qty_'.$item_index] = $value['order_qty']; // same order id so increment the counter $item_index++; } else { // new order id start at 1 $item_index = 1; } } 时，计数器不会重置为1。

我试图为我的数组实现的输出是这样的。

所需订单数组输出

item_order_id

非常感谢任何反馈或帮助。

Answer 1

你可以做两遍：

1. 按订单ID汇总订单商品
2. 构建最终输出

第一次通过

foreach($order_items as $order_id => $order_items) {
    $record = ['order_id' => $order_id];
    // add order items
    foreach($order_items as $index => $order_item) {
        foreach ($order_item as $attribute_name => $attribute_value) {
            $key = sprintf('%s_%d', $attribute_name, $index + 1);
            $record[$key] = $attribute_value;
        }
    }
    // generate csv row with record here
}

第二次通过

$("#submit").click(function(e){//now add e to your function
        e.preventDefault;//now prevent submit happen so it wont refresh
        Location.reload();
        $("#biscuit").biscuit({
           Width : $("#width").val(),//you forgot one " here
           BgColor : $("#BgColor").val(),//also you forgot one " here
        });
       });