Question

我正在尝试根据输入打印形状;形状是“x”。输入必须是正奇数整数和任意刷子字符。我已经为用户输入完成了代码，但我需要帮助实际打印形状的代码。以下是我到目前为止的情况：

 public class TestProgram {

    public static void main(String[] args) {
        int height = 5;//Any positive odd int but 5 does not work correctly. Not sure what is going on.
        char brush = '*';

        for (int row = 0; row < height/2; row++) {
            for (int i = row; i > 0; i--) {
                System.out.print(" ");
            }

            System.out.print(brush); 
            for (int i = (height/2); i >= 2*row; i--) {
                System.out.print(" "); 
            }

            System.out.print(brush);
            System.out.print("\n");

        }

        for (int row = 1; row < (height/2)+1; row++ ) {
            System.out.print(" "); 
        }
        System.out.print(brush);
        System.out.print("\n"); 
        for (int row = (height/2)-1; row >= 0; row--) {
            for (int i = row; i > 0; i--) {
                System.out.print(" ");
            }

            System.out.print(brush); 
            for (int i = (height/2); i >= 2*row; i--) {
                System.out.print(" "); 
            }

            System.out.print(brush);
            System.out.print("\n");

        }

        for (int row = 1; row < (height/2)+1; row++ ) {
            System.out.print(" "); 
        }

    }
}

Answer 1

我会从常规开始重复char n次。像

这样的东西

private static String repeat(char ch, int count) {
    StringBuilder sb = new StringBuilder();
    for (int i = 0; i < count; i++) {
        sb.append(ch);
    }
    return sb.toString();
}

然后，我希望使用String和StringBuilder例程构建repeat。像

int height = 5;
char brush = '*';
char space = ' ';
int half = height / 2;
StringBuilder sb = new StringBuilder();
for (int row = 0; row < half; row++) {
    int cols = height - ((row + 1) / 2);
    sb.append(repeat(space, row)).append(brush);
    sb.append(repeat(space, cols)).append(brush);
    sb.append(System.lineSeparator());
}
sb.append(repeat(space, half)).append(brush);
sb.append(System.lineSeparator());
for (int row = half - 1; row >= 0; row--) {
    int cols = height - ((row + 1) / 2);
    sb.append(repeat(space, row)).append(brush);
    sb.append(repeat(space, cols)).append(brush);
    sb.append(System.lineSeparator());
}
System.out.println(sb.toString());

由于您尚未了解缓冲io，因此也可以表示为

int height = 5;
char brush = '*';
char space = ' ';
int half = height / 2;
for (int row = 0; row < half; row++) {
    int cols = height - ((row + 1) * 2);
    System.out.print(repeat(space, row));
    System.out.print(brush);
    System.out.print(repeat(space, cols));
    System.out.println(brush);
}
System.out.print(repeat(space, height / 2));
System.out.println(brush);
for (int row = (height / 2) - 1; row >= 0; row--) {
    int cols = height - ((row + 1) * 2);
    System.out.print(repeat(space, row));
    System.out.print(brush);
    System.out.print(repeat(space, cols));
    System.out.println(brush);
}

如果你真的不知道如何创建方法，

int height = 5;
char brush = '*';
char space = ' ';
int half = height / 2;
for (int row = 0; row < half; row++) {
    int cols = height - ((row + 1) * 2);
    for (int t = 0; t < row; t++) {
        System.out.print(space);
    }
    System.out.print(brush);
    for (int t = 0; t < cols; t++) {
        System.out.print(space);
    }
    System.out.println(brush);
}
for (int t = 0; t < height / 2; t++) {
    System.out.print(space);
}
System.out.println(brush);
for (int row = (height / 2) - 1; row >= 0; row--) {
    int cols = height - ((row + 1) * 2);
    for (int t = 0; t < row; t++) {
        System.out.print(space);
    }
    System.out.print(brush);
    for (int t = 0; t < cols; t++) {
        System.out.print(space);
    }
    System.out.println(brush);
}

根据用户的输入打印形状

1 个答案: