Question

不幸的是，我在更换新线路时遇到了一些困难。

public class Example {

    static String s = "73167176531330624919225119674426574742355349194934\n" +
        "96983520312774506326239578318016984801869478851843\n" +
        "85861560789112949495459501737958331952853208805511\n" +
        "12540698747158523863050715693290963295227443043557\n" +
        "66896648950445244523161731856403098711121722383113\n" +
        "62229893423380308135336276614282806444486645238749\n" +
        "30358907296290491560440772390713810515859307960866\n" +
        "70172427121883998797908792274921901699720888093776\n" +
        "65727333001053367881220235421809751254540594752243\n" +
        "52584907711670556013604839586446706324415722155397\n" +
        "53697817977846174064955149290862569321978468622482\n" +
        "83972241375657056057490261407972968652414535100474\n" +
        "82166370484403199890008895243450658541227588666881\n" +
        "16427171479924442928230863465674813919123162824586\n" +
        "17866458359124566529476545682848912883142607690042\n" +
        "24219022671055626321111109370544217506941658960408\n" +
        "07198403850962455444362981230987879927244284909188\n" +
        "84580156166097919133875499200524063689912560717606\n" +
        "05886116467109405077541002256983155200055935729725\n" +
        "71636269561882670428252483600823257530420752963450".replaceAll("\\n", "");

    public static void main(String[] args) {
        System.out.println(s);
    }
}

我想从字符串\n中删除所有出现的s。我尝试在StackOverflow上查找答案，但每个帖子似乎都有不同的答案（而且它们都很复杂且难以记住）。

有一种简单的方法吗？

我也试过

replaceAll("\n", "")
replaceAll("\\\\n", "")
replaceAll(System.getProperty("line.separator"), "")
replaceAll("(\\r|\\n)", "")

Answer 1

"hello" + "world".replace("o","")

与

相同

"hello" + ("world".replaceAll("o",""))

所以replaceAll只影响字符串的最后一部分，在你的情况下是

"71636269561882670428252483600823257530420752963450".replaceAll("\\n", "").

要解决此问题，请使用括号首先连接所有字符串部分，然后替换所需的内容。

static String s = (
        "73167176531330624919225119674426574742355349194934\n" +
        "96983520312774506326239578318016984801869478851843\n" +
        "85861560789112949495459501737958331952853208805511\n" +
        "12540698747158523863050715693290963295227443043557\n" +
        "66896648950445244523161731856403098711121722383113\n" +
        "62229893423380308135336276614282806444486645238749\n" +
        "30358907296290491560440772390713810515859307960866\n" +
        "70172427121883998797908792274921901699720888093776\n" +
        "65727333001053367881220235421809751254540594752243\n" +
        "52584907711670556013604839586446706324415722155397\n" +
        "53697817977846174064955149290862569321978468622482\n" +
        "83972241375657056057490261407972968652414535100474\n" +
        "82166370484403199890008895243450658541227588666881\n" +
        "16427171479924442928230863465674813919123162824586\n" +
        "17866458359124566529476545682848912883142607690042\n" +
        "24219022671055626321111109370544217506941658960408\n" +
        "07198403850962455444362981230987879927244284909188\n" +
        "84580156166097919133875499200524063689912560717606\n" +
        "05886116467109405077541002256983155200055935729725\n" +
        "71636269561882670428252483600823257530420752963450"
    ).replaceAll("\\n", "");

但是在非现场变量的情况下，我宁愿跳过这个解决方案而不是＆＃34; one-liner＆＃34;使用简单的代码构建：

连接
修改

喜欢

//concatenation
String s =  "....."
           +"....."
           :
           +".....";

//modification
s = s.replaceAll("\\n","");

Answer 2

首先，当你在做什么时

static String s = "73167176531330624919225119674426574742355349194934\n" +
        "96983520312774506326239578318016984801869478851843\n" +
        "85861560789112949495459501737958331952853208805511\n" +
        "12540698747158523863050715693290963295227443043557\n" +
        "66896648950445244523161731856403098711121722383113\n" +
        "62229893423380308135336276614282806444486645238749\n" +
        "30358907296290491560440772390713810515859307960866\n" +
        "70172427121883998797908792274921901699720888093776\n" +
        "65727333001053367881220235421809751254540594752243\n" +
        "52584907711670556013604839586446706324415722155397\n" +
        "53697817977846174064955149290862569321978468622482\n" +
        "83972241375657056057490261407972968652414535100474\n" +
        "82166370484403199890008895243450658541227588666881\n" +
        "16427171479924442928230863465674813919123162824586\n" +
        "17866458359124566529476545682848912883142607690042\n" +
        "24219022671055626321111109370544217506941658960408\n" +
        "07198403850962455444362981230987879927244284909188\n" +
        "84580156166097919133875499200524063689912560717606\n" +
        "05886116467109405077541002256983155200055935729725\n" +
        "71636269561882670428252483600823257530420752963450".replaceAll("\\n", "");

您只是替换该字符串的最后一个连接（注意：它没有"\n"）。

您需要做的是在字符串声明中删除replaceAll，并在主方法中执行s = s.replaceAll("\n", "");，如下所示：

public static void main(String[] args) {
    s = s.replaceAll("\n", "");
    System.out.println(s);
}

经过测试和工作：D 希望这有用：D

Answer 3

您可以在打印之前拆分并加入字符串，如下所示：

public static void main(String[] args) {
    System.out.println(String.join("", s.split("\n")));
}

如何更换新线

3 个答案: