Question

我试图创建一个网页，使用ajax将javascript数组写入mySql表，以调用.php脚本。当我点击我的div（.button）时，我从jQuery.min库中得到了这个错误 - TypeError: Illegal constructor.，从未见过它。知道什么是错的吗？没有提供一个小提琴，因为有一个.php文件，如果你想看到它的实际效果，将整个内容上传到here。谢谢你的帮助

HTML：

    <!doctype HTML>
<head>

<meta charset="UTF-8">

</head>

<body>
tis just a blank page to get scripts and whatnot
<br>
<br>
<div class="button">CLICK</div>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
<script src="index.js"></script>

</body>

的javascript：

var strings = [];

for(x=0;x<45;x++) {
    strings.push([1,2,3]);
}

$('.button').click(function() {
    makeAjaxRequest();
    });

function makeAjaxRequest() {
    $.ajax({
        url: 'write.php',   //where I'm sending data
        type: 'get',    //data type post/get
        data: {name: $(strings)},   //The data to be send in a query string format or JSON
        success: function(response) { //A callback function to be executed is the request was succesful. A ‘response’ variable will be returned.
            console.log(response);
        }
    });
}

PHP：

 <?php
$servername = "localhost";
$username = "topdecka_wtAdmin";
$password = "OnlyWr1te";
$dbname = "topdecka_writeTest";

$data = "%".$_GET['name']."%";  //data passed from strings variable
try {
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
    // set the PDO error mode to exception
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    // sql to create table
    $sql = "CREATE TABLE strings (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    strings TEXT NOT NULL,
    INSERT INTO strings (strings)
    VALUES ('$data')    
    )";

    // use exec() because no results are returned
    $conn->exec($sql);

    echo "Table string created successfully";
    }
catch(PDOException $e)
    {
    echo $sql . "<br>" . $e->getMessage();
    }

$conn = null;
?>

TypeError：非法构造函数

0 个答案: