在Web视图中单击HTML按钮上的打开Android活动

时间:2015-03-26 10:06:30

标签: android android-webview

我有一个Android程序,可以在Web视图中显示HTML页面。 HTML页面存在于" asset / www / index.html"。

我想在HTML页面上放置一个按钮,并在单击按钮时打开一个新活动。

这是Java代码:

public class HelloWebApp extends Activity {
    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        WebView webView = (WebView)findViewById(R.id.webView);
        webView.getSettings().setJavaScriptEnabled(true);
        webView.setWebChromeClient(new WebChromeClient());
        webView.loadUrl("file:///android_asset/www/index.html");
    }
}

1 个答案:

答案 0 :(得分:1)

您必须在html按钮点击时传递网址,如下所示

<强>的index.html

<html>
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width; user-scalable=0;" />
<script type="text/javascript" charset="utf-8" src="jquery-2.0.0.min.js"></script>
<script type="text/javascript" charset="utf-8" src="quantize.js"></script>

<title>My HTML</title>
</head>
<body>
<h1>My HTML</h1>
<INPUT TYPE="button" value="Test" onClick="window.location='Navigation://OpenNativeScreen'">
</body>
</html>

现在,当按钮点击时,您将在网页视图的 shouldOverrideUrlLoading 方法中获取该网址。请参阅以下代码,

<强> MainActivity.java

public class MainActivity extends Activity {

WebView myBrowser;

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.dropdown_html);
    myBrowser = (WebView) findViewById(R.id.mybrowser);
    myBrowser.setWebViewClient(new MyBrowser());
    myBrowser.getSettings().setJavaScriptEnabled(true);
    myBrowser.loadUrl("file:///android_asset/www/index.html");
}

private class MyBrowser extends WebViewClient {

    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (url.equals("Navigation://OpenNativeScreen")) {
            startActivity(new Intent(MainActivity.this,SecondActivity.class));
            finish();
            return true;
        }
        return false;
    }       
   }
 }
相关问题