MySQL从结果中获得平均值,平均值必须在8到12之间

时间:2015-03-28 00:38:53

标签: mysql sql sql-server average

所以我试图创建一个MySQL查询来获得RANK id的平均值,它必须介于8到12之间,否则查询将选择5个随机播放器名称,直到RANKVALUE平均在8到12之间。

select summonername 
from (select rankvalue from 
players group by summonername 
having count(rankvalue) = 5 
order by rand())
group by summonername
having avg(rankvalue) between 8 and 12

tid  PLAYER NAME   RANKVALUE
1   summonername2   5
1   Summoner 1      22
1   Summoner 2      10
1   Summoner 3      14
1   Summoner 4      10
1   Summoner 2      21
1   test            21
1   yop             13
1   summonername6   12
1   summonername7   16
1   summonername8   5
1   summonername9   13
1   summonername10  21
1   summonername11  1
1   summonername12  9

1 个答案:

答案 0 :(得分:0)

使用Group byHaving子句

SELECT `summonername`, AVG(rankvalue)
FROM `players` 
Where tid=1 
group by summonername
Having AVG(rankvalue) between 8 and 12
ORDER BY rand() LIMIT 5