所以我试图创建一个MySQL查询来获得RANK id的平均值,它必须介于8到12之间,否则查询将选择5个随机播放器名称,直到RANKVALUE平均在8到12之间。
select summonername
from (select rankvalue from
players group by summonername
having count(rankvalue) = 5
order by rand())
group by summonername
having avg(rankvalue) between 8 and 12
tid PLAYER NAME RANKVALUE
1 summonername2 5
1 Summoner 1 22
1 Summoner 2 10
1 Summoner 3 14
1 Summoner 4 10
1 Summoner 2 21
1 test 21
1 yop 13
1 summonername6 12
1 summonername7 16
1 summonername8 5
1 summonername9 13
1 summonername10 21
1 summonername11 1
1 summonername12 9
答案 0 :(得分:0)
使用Group by
和Having
子句
SELECT `summonername`, AVG(rankvalue)
FROM `players`
Where tid=1
group by summonername
Having AVG(rankvalue) between 8 and 12
ORDER BY rand() LIMIT 5