Question

我一直无法获得依赖于另一个函数输出的函数。当我运行以下代码时（这是一个非常简化的版本）...

from random import randint

def event():
    if m == 1:
        r = randint(0, 4)
    else:
        r = randint(3, 7)

def random():
    if r == 1:
        print "Test A"
    elif r == 2:
        print "Test B"
    elif r == 3:
        print "Test C"
    elif r == 4:
        print "Test D"
    elif r == 5:
        print "Test E"
    elif r == 6:
        print "Test F"


m = 1
event()
random()

m = 2
event()
random()

m = 3
event()
random()

......我得到NameError: global name 'r' is not defined

我需要将它们保存在单独的函数中，因为在我的实际代码中它们非常复杂。如何让random（）识别event（）生成的随机数？

Answer 1

一种简单的方法是使用return和args

def event():
    if m == 1:
        r = randint(0, 4)
    else:
        r = randint(3, 7)
    return r                        # return variable r here


r = event()                         # accept variable r here from event
random(r)                           # pass it to random function

def random(r)                       # receive r from the caller
    ....                            # Use r as a variable

Answer 2

虽然返回变量是实现目标的好方法，但有时您需要拥有global个变量。在这种情况下，请在分配global r之前将event()添加到def event(): global r if m == 1: r = randint(0, 4) else: r = randint(3, 7)的定义中。 e.g：

{{1}}

引用其他函数输出的函数 - Python

2 个答案: