Question

我对我的数据库进行了查询，该查询对他们完成的日期进行了采访，我需要能够仅提取当前月份和年份的采访，并计算他们然后将他们与采访人员进行分组

PHP

$time = time();

QUERY

select count(i.interv_id) as cnt, u.user_name, year(from_unixtime($time)) as year, month(from_unixtime($time)) as month
from support.support_interviews as i
left join support.support_logs as l on l.log_id = i.log_id
left join support.support_users as u on u.user_id = l.user_id
group by u.user_name, month, year
order by cnt desc

这个查询工作正常，我得到了我想要的东西，但我计算了表格中的所有数据。

表结构

CREATE TABLE support_interviews (
  interv_id int(11) NOT NULL AUTO_INCREMENT,
  log_id int(11) NOT NULL,
  interv_date int(11) NOT NULL,
  interv_url varchar(255) NOT NULL,
  PRIMARY KEY (interv_id)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=36 ;

DATA

INSERT INTO `support_interviews` VALUES(1, 1, 1413849800, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(2, 1, 1413849800, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(3, 1, 1413849800, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(4, 2, 1413936200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(5, 2, 1413936200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(6, 3, 1414973000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(7, 3, 1414973000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(8, 3, 1414973000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(9, 3, 1414973000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(10, 4, 1415750600, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(11, 4, 1415750600, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(12, 5, 1415837000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(13, 6, 1416096200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(14, 6, 1416096200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(15, 6, 1416096200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(16, 6, 1416096200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(17, 6, 1416096200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(18, 6, 1416096200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(19, 7, 1416701000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(20, 7, 1416701000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(21, 7, 1416701000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(22, 7, 1416701000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(23, 7, 1416701000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(24, 8, 1417392200, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(25, 9, 1418342600, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(26, 9, 1418342600, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(27, 9, 1418342600, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(28, 10, 1418429000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(29, 10, 1418429000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(30, 10, 1418429000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(31, 10, 1418429000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(32, 10, 1418429000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(33, 10, 1418429000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(34, 10, 1418429000, 'http://somesite.com/interviewlink');
INSERT INTO `support_interviews` VALUES(35, 10, 1418429000, 'http://somesite.com/interviewlink');

Answer 1

如果您只想获得当前月份和年份的访谈，解决方案是在SQL语句中添加WHERE子句

SELECT * 
FROM table
WHERE date_format(from_unixtime(interv_date),'%Y-%m')=date_format(now(), '%Y-%m')

Answer 2

您在now()上使用from_unixtime，然后应用year功能。这将返回null

mysql> select year(from_unixtime(now()));
+----------------------------+
| year(from_unixtime(now())) |
+----------------------------+
|                       NULL |
+----------------------------+
1 row in set (0.00 sec)

如果您现在尝试查找年份和月份，则可以直接使用now()

上的功能

mysql> select year(now());
+-------------+
| year(now()) |
+-------------+
|        2015 |
+-------------+
1 row in set (0.00 sec)


mysql> select month(now());
+--------------+
| month(now()) |
+--------------+
|            3 |
+--------------+
1 row in set (0.00 sec)

无法从数据库中获取当前月份和年份

2 个答案: