Question

我有一个小脚本，它从我的客户端获取用户名和密码，如果他们的凭据是正确的，他们将被带到我的开发服务器上的他们的站点目录。

if条件完美无缺，并响应与我的MySQL数据库中的计数器部分匹配的正确凭据。

但是，else条件根本不会执行（即，如果用户的凭据是incorret，则不会将用户定向到错误页面）。我认为while循环可能会使逻辑跳闸，但我需要$row变量来从DB获取目录字段。

有什么想法吗？

$username = stripslashes($_POST['username']);
$password = stripslashes($_POST['password']);

$pass = md5($password);

$conn = mysqli_connect("localhost", "root", "", "digital_server");
$sql = "SELECT * FROM projects WHERE username = '$username' AND password = '$pass'";

$query = mysqli_query($conn, $sql);

while($row = mysqli_fetch_assoc($query)) {

    if($query) {
        header("Location: " . $row['directory'] . "/");
    } 

    else {
        header("Location: http://dev.myserver.com/error.php");
    }
}

分辨非常感谢所有帮助过的人。

修改后的代码块 删除了while并创建了一个$row变量来获取if逻辑所需的数据

    $row = mysqli_fetch_assoc($query);

    if(mysqli_num_rows($query) > 0) {
        header("Location: " . $row['directory'] . "/");
    } 

    else {
        header("Location: http://dev.myserver.com/error.php");
    }

Answer 1

// No need of while here
//while() {     
    if( mysqli_num_rows($query) > 0 ) {
    $row = mysqli_fetch_assoc($query);
        header("Location: " . $row['directory'] . "/");
    } else {
        header("Location: http://dev.myserver.com/error.php");
    }

选项2

$sql = "SELECT * FROM projects WHERE username = '$username' AND password = '$pass'";
$query = mysqli_query($conn, $sql);
$row = mysqli_fetch_array($query);

   if(count($row ) > 0 ) {
            header("Location: " . $row['directory'] . "/");
        } else {
            header("Location: http://dev.myserver.com/error.php");
        }

Answer 2

您可能正在寻找mysqli_num_rows($result);

$query = mysqli_query($conn, $sql);
if( mysqli_num_rows($query) > 0 ) {
  $row = mysqli_fetch_assoc($query);
  header("Location: " . $row['directory'] . "/");
}else{
  header("Location: http://dev.myserver.com/error.php");
}

您始终可以使用查询来捕获查询中的错误 mysqli_error

Answer 3

        $username = stripslashes($_POST['username']);
        $password = stripslashes($_POST['password']);

        $pass = md5($password);

        $conn = mysqli_connect("localhost", "root", "", "digital_server");
        $sql = "SELECT * FROM `projects` WHERE `username` = '$username' AND `password` = '$pass'";

        $query = mysqli_query($conn, $sql);

       if( mysqli_num_rows($query) > 0 ) {
     $row = mysqli_fetch_assoc($query);
      header("Location: " . $row['directory'] . "/");
    }
else
{
      header("Location: http://dev.myserver.com/error.php");
    }

PHP登录if / else条件不执行其他条件

3 个答案: