SQL CASE WHEN STATEMENt进入PHP VARIABLE

时间:2015-04-01 12:21:52

标签: php sql variables

我有这个问题:

我有SQL声明:

SELECT Amount FROM cicmpy 
  INNER JOIN (SELECT DealerCode, sum(Amount) as Amount FROM 
    (SELECT DealerCode, LOG as LogtLimit,TemporaryCreditLimit as TemporaryCreditLimit,
            CASE WHEN  TemporaryCreditLimit>0 then TemporaryCreditLimit ELSE LOG END as Amount 
            FROM LOG_DATA WHERE Status = 1 group by DealerCode) x
    on x.DealerCode=debcode where debnr is not NULL and ltrim(debcode) = '21021287'`

我希望这个语句进入php $查询变量。

1 个答案:

答案 0 :(得分:0)

  

尝试这样,它将解决您的错误。

$sql = "Put your query";    //put your query in php variable
$result = mysql_query($sql) or die(mysql_error());
while($row=mysql_fetch_array($result)) {
do stuff...
}
  

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