Question

我已经有了代码 - 请查看下面的内容。这段代码工作正常但我只是意识到它只将文件添加到uploads文件夹中，并且不会向数据库添加任何内容。有人可以帮我填空吗？我想使用一个数组，并尽可能简单。

请向下滚动到执行代码的注释，图像会进入文件夹。

uploader.php

<?php
if (isset($_POST['submit'])) {
$j = 0;     // Variable for indexing uploaded image.

$target_path = "uploads/test/";     // Declaring Path for uploaded images.

for ($i = 0; $i < count($_FILES['file']['name']); $i++) {
// Loop to get individual element from the array

$validextensions = array("jpeg", "jpg", "png");      
// Extensions which are allowed.

$ext = explode('.', basename($_FILES['file']['name'][$i]));   
// Explode file name from dot(.)

$file_extension = end($ext); 
// Store extensions in the variable.

$target_path = $target_path . md5(uniqid()) . "." . $ext[count($ext) - 1];
// Set the target path with a new name of image.

$j = $j + 1;      
// Increment the number of uploaded images according to the files in array.

if (($_FILES["file"]["size"][$i] < 100000)     
// Approx. 100kb files can be uploaded.

&& in_array($file_extension, $validextensions)) {

if (move_uploaded_file($_FILES['file']['tmp_name'][$i], $target_path)) {
// If file moved to uploads folder.

?>

<div id="noerror">Image <?php echo $j;?>-->Image Uploaded!</div>

<?php

// File was moved, so execute code here

// In this code I would like to add file name to a DB 


} else {     //  If File Was Not Moved.
?>

<div id="error">Image <?php echo $j;?>--> <b>Please Try Again!</b></div>

<?php
}

} else {     //   If File Size And File Type Was Incorrect.
?>

<div id="error">Image <?php echo $j;?>--> <b>Check file Size or Type</b></div>

<?php
}
}
}
?>

Answer 1

你在寻找这样的东西：

请在以下查询中添加database field names和database table name：

mysqli_query("INSERT INTO `images` SET `image_name` = '".$_FILES['file']['name'][$i]."'") or die (mysqli_error());

您的代码现在应该是：

<?php
if (isset($_POST['submit'])) {
$j = 0;     // Variable for indexing uploaded image.

$target_path = "uploads/test/";     // Declaring Path for uploaded images.

for ($i = 0; $i < count($_FILES['file']['name']); $i++) {
// Loop to get individual element from the array

$validextensions = array("jpeg", "jpg", "png");      
// Extensions which are allowed.

$ext = explode('.', basename($_FILES['file']['name'][$i]));   
// Explode file name from dot(.)

$file_extension = end($ext); 
// Store extensions in the variable.

$target_path = $target_path . md5(uniqid()) . "." . $ext[count($ext) - 1];
// Set the target path with a new name of image.

$j = $j + 1;      
// Increment the number of uploaded images according to the files in array.

if (($_FILES["file"]["size"][$i] < 100000)     
// Approx. 100kb files can be uploaded.

&& in_array($file_extension, $validextensions)) {

if (move_uploaded_file($_FILES['file']['tmp_name'][$i], $target_path)) {
// If file moved to uploads folder.

?>

<div id="noerror">Image <?php echo $j;?>-->Image Uploaded!</div>

<?php

// File was moved, so execute code here

mysqli_query("INSERT INTO `images` SET `image_name` = '".$_FILES['file']['name'][$i]."'") or die (mysqli_error()); // In this code I would like to add file name to a DB 



} else {     //  If File Was Not Moved.
?>

<div id="error">Image <?php echo $j;?>--> <b>Please Try Again!</b></div>

<?php
}

} else {     //   If File Size And File Type Was Incorrect.
?>

<div id="error">Image <?php echo $j;?>--> <b>Check file Size or Type</b></div>

<?php
}
}
}
?>

Answer 2

由于以下原因，您的代码对我来说非常混乱：

没有合适的缩进
与代码相同的注释难以阅读

以下是我要做的事情：

<?php

if (isset($_POST['submit'])) {
// Variable for indexing uploaded image.
$j = 0;
// Declaring Path for uploaded images.
$target_path = "uploads/test/";

// Loop to get individual element from the array
for ($i = 0; $i < count($_FILES['file']['name']); $i++) {

    // Extensions which are allowed.
    $validextensions = array("jpeg", "jpg", "png");      

    // Explode file name from dot(.)
    $ext = explode('.', basename($_FILES['file']['name'][$i]));   

    // Store extensions in the variable.
    $file_extension = end($ext); 
    // Set the target path with a new name of image.
    $target_path = $target_path . md5(uniqid()) . "." . $ext[count($ext) - 1];

    // Increment the number of uploaded images according to the files in array.
    $j = $j + 1;      

    if (($_FILES["file"]["size"][$i] < 100000) && in_array($file_extension, $validextensions)) {

        // If file moved to uploads folder.
        if (move_uploaded_file($_FILES['file']['tmp_name'][$i], $target_path)) {

            echo '<div id="noerror">Image '.$j.'-->Image Uploaded!</div>';

            // File was moved, so execute code here
            //Connection to DB

            $mysqli = new mysqli("localhost", "my_user", "my_password", "table_name");

            // check connection
            if ($mysqli->connect_errno) {
                printf("Connect failed: %s\n", $mysqli->connect_error);
                exit();
            }

            $mysqli->query("INSERT INTO images_table (img_column_1) VALUES ('".$_FILES['file']['tmp_name'][$i]."')");

            //Close DB connection
            mysqli_close($con);

        //  If File Was Not Moved.
        } else {

            echo '<div id="error">Image '.$j.'--> <b>Please Try Again!</b></div>';
        }

    //If File Size And File Type Was Incorrect.
    } else {   

        echo '<div id="error">Image '.$j.'--> <b>Check file Size or Type</b></div>';

    }  
}
}
?>

我通常不建议使用：

echo '<div>'.$var.'</div>'

但是你的代码非常混乱，我认为这是一个更好的解决方案。

使用数组将多个图像名称插入数据库

2 个答案: