Question

我有一个问题。我基本上完成了我的程序，除了我创建的while循环的最后一个中断。如果我输入-1以突破我的第一个输出问题“输入产品编号（1-5）或-1退出”，它会突破而没有问题。如果我在第二个问题“输入数量或-1退出”期间输入-1，它只会循环回到下一个产品编号请求。

我已经尝试查找有关打破while循环的一些其他信息，并尝试将相同的逻辑应用于我现有的代码。不幸的是，我仍然遇到同样的问题。它没有出现这个特殊的请求是一个重复的问题，所以我觉得安全问它。我做错了什么，因为经过大约一个小时的努力解决这个问题后，我只是疯了。任何方向将不胜感激。

谢谢，

PROG

import java.util.Scanner;

public class ModuleFour {

public static void main(String[] args) {

    int pNumber = 0; //declaring integer for Product Number
    int pQuantity= 0; //declaring integer quantity of Product
    double totalcost = 0; //declaring double for Total Cost of combined Product
    double cost = 0; //declaring double for cost of each Product
        Scanner productTotal = new Scanner(System.in); //create scanner productTotal
        pNumber = 0;
        pQuantity = 0;
    while (pNumber >= 0 && pNumber <=5) //set condition of pNumber for while loop
    {
        System.out.println("Enter Product Number (1-5) or -1 to Quit"); //print out asking for input
        pQuantity = productTotal.nextInt(); //
    switch(pQuantity) { //begin switch statement
    case 1: //start of cases, all are the same. 
        System.out.println("Product " + (pNumber+1));
        System.out.println("Enter Quantity or -1 to Quit");
        pQuantity = productTotal.nextInt(); 
        cost = 2.98; //declare cost of case 1. Same method for each case. 
        totalcost = totalcost + cost*pQuantity; //setting totalcost algorithm.
        System.out.println("Current total cost: " + totalcost); //print out the current totalcost.
        pNumber++; //increase value of pNumber by 1. Same for each case. 
    break; //break out of Case 1. Same for each case.
    case 2:
        System.out.println("Product " + (pNumber+1));
        System.out.println("Enter Quantity or -1 to Quit");
        pQuantity = productTotal.nextInt();
        cost = 4.50;
        totalcost = totalcost + cost*pQuantity;
        System.out.println("Current total cost: " + totalcost);
        pNumber++;
    break;
    case 3:

        System.out.println("Product " + (pNumber+1));
        System.out.println("Enter Quantity or -1 to Quit");
        pQuantity = productTotal.nextInt();
        cost = 9.98;
        totalcost = totalcost + cost*pQuantity;
        System.out.println("Current total cost: " + totalcost);
        pNumber++;
    break;
    case 4:
        System.out.println("Product " + (pNumber+1));
        System.out.println("Enter Quantity or -1 to Quit");
        pQuantity = productTotal.nextInt();
        cost = 4.49;
        totalcost = totalcost + cost*pQuantity;
        System.out.println("Current total cost: " + totalcost);
        pNumber++;
    break;
    case 5:
        System.out.println("Product " + (pNumber+1));
        System.out.println("Enter Quantity or -1 to Quit");
        pQuantity = productTotal.nextInt();
        cost = 6.87;
        totalcost = totalcost + (cost*pQuantity);
        System.out.println("Current total cost: " + totalcost);
        pNumber++;
    case -1: //declare case for -1 to break out of while loop
        ****pNumber = -1; //set condition for pNumber to break out of loop with input of -1.
        pQuantity = -1; //set condition for pQuantity to break out of loop with input of -1.****
    break; //when condition is met (-1 as input) break out of while loop.
    }
        System.out.println("Total cost-->" +totalcost); //print out the final total cost
    }

}

}

Answer 1

在switch语句中不需要case -1。相反，你可以添加pQuantity的条件＆gt; 1进入while条件如下：

while ((pNumber >= 0 && pNumber <=5) || ( pQuantity >1))

现在，如果你输入-1到第一个问题，它退出程序不是因为最后一个案例-1条件，而是因为while循环条件。但是当您在第二个问题（产品数量）中输入-1时，它将转到相应的大小写条件，完成并退出switch语句并返回while循环。它不会去案例-1条件检查。

输入数量时出现问题

1 个答案: